## LeetCode 21 合并链表 ## 引用官方代码,定义结点类 class ListNode: def __init__(self, x): self.val = x self.next = None 将数组转换为链表,也可以理解为链表的创建(官网不给出): ## 将给出的数组,转换为链表 def linkedlist(list): head = ListNode(list[0]) ## 列表的第一个元素。这里...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 1. 2. # Definition for singly-linked list. # class ListNode(object)...
next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/problem LeetCode 日更第 52 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据结构不一样,这里是合并链表。 由于是链...
}if($l1->val <=$l2->val) {$l1->next =mergeTwoLists($l1->next,$l2);return$l1; }if($l2->val <=$l1->val) {$l2->next =mergeTwoLists($l2->next,$l1);return$l2; } }/** * 构建一个单链表(将数组转换成链表) */functioncreateLinkedList($arr){$linkedList= [];$current=newListN...
LeetCode-cn Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. Example 1: Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4] ...
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list ...
题目详情 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. <a href="https://leetcode.com/problems/merge-two-sorted-lists/" target="_blank">Leetcode Link</a> ...
面试题 10.01. 合并排序的数组 - 给定两个排序后的数组 A 和 B,其中 A 的末端有足够的缓冲空间容纳 B。 编写一个方法,将 B 合并入 A 并排序。 初始化 A 和 B 的元素数量分别为 m 和 n。 示例: 输入: A = [1,2,3,0,0,0], m = 3 B = [2,5,6], n = 3 输出: [1,
You are given the heads of two sorted linked lists list1 and list2.Merge the two lists into one sorted list. The list should be made by splicing together the nodes of the first two lists.Return the head of the merged linked list.impl Solution { pub fn me