【leetcode】21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 Tip:将两个有序链表融合,按照val值...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 解法1: 递归 https://mp.weixin.qq.com/s/7Tqc84twkk3bRmIebxwWAg 自...
leetcode 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Seen this question in a real interview before? Yes
https://leetcode.com/problems/merge-two-sorted-lists/ 题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路: easy 。 算法: AI检测代码解析 ...
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4,1->3->4Output:1->1->2->3->4->4 ...
# Definition for singly-linked list. class ListNode: def __init__(self, x): self.val = x self.next = None class Solution: def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode: head = ListNode(0) first = head while l1 and l2: if l1.val > l2.val: head.next = ...
21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4...
2015-07-13 10:31 − https://leetcode.com/problems/merge-two-sorted-lists/ 1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ... 阿怪123 0 122 Merge Two Sorted Lists 2015-09-25 19:48 − Merge two sorted linked lists and return it...
## LeetCode 21 合并链表 ## 引用官方代码,定义结点类 class ListNode: def __init__(self, x): self.val = x self.next = None 将数组转换为链表,也可以理解为链表的创建(官网不给出): ## 将给出的数组,转换为链表 def linkedlist(list): head = ListNode(list[0]) ## 列表的第一个元素。这里...
next = list1; } else { // 如果 list1 没有结点,表明 list2 已遍历完成, // 则将 list2 直接放在 tail 后面 tail.next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/...