Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 因为没有空间要求,所以想到ListNode*head = new ListNode(INT_MIN);重新定义一...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 这个题目思路就是用dummy node,然后依次判断是l1 小还是l2小,最后当一方是...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并2个有序链表 2、代码实现 AI检测代码解析 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Seen this question in a real interview before? Yes 简单的归并排序,不说了,直接上代码: AI检测代码解析 /** * Definition for singly-linked list. ...
You are given the heads of two sorted linked lists list1 and list2. Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists. Return the head of the merged linked list. Example 1: 代码语言:javascript 代码运行次数:0 运行...
Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing(拼接) together the nodes of the first two lists. The sorted list is in ascending order. typedef struct _ListNode { int val; struct _ListNode *next;...
Can you solve this real interview question? Merge k Sorted Lists - You are given an array of k linked-lists lists, each linked-list is sorted in ascending order. Merge all the linked-lists into one sorted linked-list and return it. Example 1: Inpu
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We now merge these two runs back into the original array, resulting in the final sorted list. In general, one can go back and forth (i.e., ping-pong) in this manner between the two arrays until all runs have been merged. This style of merging has several benefits: The ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 思路: 合并两个有序链表,做法有两种,递归和迭代,递归的条件就是返回两个节点中...