next return list class Solution: def mergeTwoLists(self, head1, head2): if not head1: # 如果head1为空,直接返回head2 return head2 if not head2: # 如果head2为空,直接返回head1 return head1 pre = ListNode(0) # 使用哑结点简化操作 head = pre while head1 and head2: if head1.val ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. » Solve this problem [Thoughts] 简单的实现,也没什么可说的。 [Code] 1:ListNode*mergeTwoLists(ListNode*l1,ListNode*l2){ 2:if(l1==NULL)retur...
题目:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lis 相对还是简单的,直接合并。 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) ...
Both list1 and list2 are sorted in non-decreasing order. 方法一:递归 思路及算法 如果list1或list2是空链表 ,只需要返回非空链表。否则,要判断list1和list2哪一个链表的头节点的值更小,然后递归地决定下一个添加到结果里的节点。如果两个链表有一个为空,递归结束。 class Solution { fun mergeTwoLists(...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. C++代码如下: #include<iostream>#include<new>usingnamespacestd;//Definition for singly-linked list.structListNode ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Seen this question in a real interview before? Yes 简单的归并排序,不说了,直接上代码:
Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing(拼接) together the nodes of the first two lists. The sorted list is in ascending order. typedef struct _ListNode { int val; struct _ListNode *next;...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Solution1:Iterative遍历 思路:持续遍历比较,将小的relink到新的结果list。最后将多余的link一下 ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题意 将两个有序链表合并 ...
21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4...