解法二:申请额外的O(m+n)的存储空间保存合并后数组,则从头往后遍历两个排序数组即可。时间复杂度O(m+n),空间复杂度O(m+n)。 class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { if (m <= 0 && n <= 0) return; int a
LeetCode 88. Merge Sorted Array 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and ...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. 这道题很...
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn 按照归并排序的惯性思...
[leetcode] 88. Merge Sorted Array Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has a size equal to m + n such that...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. ...
给你两个按非递减顺序排列的整数数组nums1和nums2,另有两个整数m和n,分别表示nums1和nums2中的元素数目。 请你合并nums2到nums1中,使合并后的数组同样按非递减顺序排列。 注意:最终,合并后数组不应由函数返回,而是存储在数组nums1中。为了应对这种情况,nums1的初始长度为m + n,其中前m个元素表示应合并的元...
## LeetCode 21 合并链表 ## 引用官方代码,定义结点类 class ListNode: def __init__(self, x): self.val = x self.next = None 将数组转换为链表,也可以理解为链表的创建(官网不给出): ## 将给出的数组,转换为链表 def linkedlist(list): head = ListNode(list[0]) ## 列表的第一个元素。这里...
题目:88. Merge Sorted Array 思路: 这题很直观的可以看出由于两个数组都是排好序的,我们只需要从头到尾或从尾到头同时扫描两个数组,对比扫描到的值,取较大或较小的一个往第一个数组中摆放。把第二个数组合并进第一个数组既可以从前往后比较每次插入比较小的值到第一个数组中,也可以从后往前比较每次把较大...
. - 备战技术面试?力扣提供海量技术面试资源,帮助你高效提升编程技能,轻松拿下世界 IT 名企 Dream Offer。