Leetcode 88. 合并两个有序数组Merge Sorted Array 旧瞳新梦 来自专栏 · Leetcode每日一题array篇 中文题目 给你两个按 非递减顺序 排列的整数数组 nums1 和 nums2,另有两个整数 m 和 n ,分别表示 nums1 和 nums2 中的元素数目。
代码(Python3) class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ # i/j 分别表示 nums1/nums2 中还未使用的最大数的下标 i, j = m - 1, n - 1 # k 表示 nums...
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal tom+n) to hold additional elements from B. The number of elements initialized in A and B aremandnrespectively. 代码:oj测试通过 R...
class Solution { public: void merge(int A[], int m, int B[], int n) { int i=m-1; int j=n-1; int k = m+n-1; while(i >=0 && j>=0) { if(A[i] > B[j]) A[k--] = A[i--]; else A[k--] = B[j--]; } while(j>=0) A[k--] = B[j--]; } }; py...
class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { if(nums1.empty() || nums2.empty()) return; while(m > 0 && n > 0){ if(nums1[m-1] < nums2[n-1]){ nums1[m + n -1] = nums2[n - 1]; ...
Leetcode No.88 Merge Sorted Array(c++实现) 1. 题目 1.1 英文题目 You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. ...
# @lc app=leetcode id=88 lang=python # # [88] Merge Sorted Array ## @lc code=start class Solution(object): def merge(self, nums1, m, nums2, n): """ :type nums1: List[int] :type m: int :type nums2: List[int] :type n: int ...
# Given two sorted integer arrays A and B, merge B into A as one sorted array. # # Note: # You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. # The number of elements initialized in A and B are m and n...
更多关于 python3 语言特性请参见书籍: 《流畅的Python》 代码 classSolution:defmerge(self,nums1:List[int],m:int,nums2:List[int],n:int)->None:"""Do not return anything, modify nums1 in-place instead."""if0==n:passelif0==m:nums1[:n]=nums2[:n]else:a,b=m-1,n-1k=m+n-1while...
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