方法1: 1publicclassSolution {2publicvoidmerge(int[] nums1,intm,int[] nums2,intn) {3//特别注意这里的m只是nums1中元素的个数,不是最终第一个数组的长度 不要用m=nums1.length;不然会造成数据越界的报错45inti=m-1,j=n-1,index=m+n-1;67while(i>=0&&j>=0){8if(nums1[i]>nums2[j]){...
publicstaticvoidmain(String[] args){ Easy_088_MergeSortedArray instance =newEasy_088_MergeSortedArray();int[] nums1 = {1,2,2,3,4,5,0,0,0};intm =6;int[] nums2 = {2,5,8};intn =3;longstart = System.nanoTime(); instance.merge(nums1, m, nums2, n);longend = System.nano...
来自专栏 · LeetCode Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal...
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn 按照归并排序的惯性思...
class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ # i/j 分别表示 nums1/nums2 中还未使用的最大数的下标 i, j = m - 1, n - 1 # k 表示 nums1 中下一个该...
https://leetcode.com/problems/merge-sorted-array/ 因为这里要求in place 修改nums1.所以不要新申请一个list。小trick就是two pointers 从list末尾开始scan。最后要注意n > m的时候,还要把剩余的nums2加到nums1中 http://chaoren.is-programmer.com/posts/42844.html ...
Forjava, it's difficult to extend array, thus difficult to construct a new slot to save infinity2147483647. We can usemodulusto accomplish this target, as long as we set the visited slot to be infinity. Running time isO(m+n). classSolution{publicvoidmerge(int[]nums1,intm,int[]nums2,...
So I've tried to do it recursively, and it gets really messy, as I need another helper function splitArrayInToTwo() to help me split it, and while I'm doing that the run time is O(n), because java's array cannot simply use ":" to divide, I would have to copy each node one...
[Leetcode] Merge Sorted Array 合并数组 Merge Sorted Array 最新更新请见:https://yanjia.me/zh/2019/02/... Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is greater or equal to...
java: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{publicvoidmerge(int[]nums1,int m,int[]nums2,int n){int i=m-1,j=n-1,k=m+n-1;while(i>=0&&j>=0)nums1[k--]=nums1[i]>=nums2[j]?nums1[i--]:nums2[j--];while(j>=0)nums1[k--]=nums2[j--];}}...