class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { if (m <= 0 && n <= 0) return; int a = 0, b = 0; int C[m + n]; for (int i = 0; i < m + n; ++i) { if (a < m && b < n) { i
来自专栏 · LeetCode Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal...
题目链接: Merge Sorted Array : leetcode.com/problems/m 合并两个有序数组: leetcode.cn/problems/me LeetCode 日更第 143 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-06-08 08:22 力扣(LeetCode) 数组 Python 赞同1添加评论 分享喜欢收藏申请转载 ...
Leetcode No.88 Merge Sorted Array(c++实现) 1. 题目 1.1 英文题目 You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. Merge nums1 and nums2 into a single array ...
[leetcode] 88. Merge Sorted Array Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has a size equal to m + n such that...
Leetcode: Merge Sorted Array 题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and ...
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之前做过两个有序链表的排序插入Leetcode21 Merge Two Sorted Lists。当时有暴力循环迭代的方法,还有递归的方法。每次加入一个元素,然后对剩下的元素继续调用函数进行排序插入。 这次是k个,感觉总体思路不会差太多。如果我们想要继续使用递归的方法,对于参数的处理就不会合并两个链表一样简单。因为当时只有两个参数,...
*/public ListNodemergeTwoLists(ListNode l1,ListNode l2){// write your code hereListNode dummy=newListNode(0);ListNode lastNode=dummy;while(l1!=null&&l2!=null){if(l1.val<l2.val){lastNode.next=l1;l1=l1.next;}else{lastNode.next=l2;l2=l2.next;}lastNode=lastNode.next;}if(l1!=null){...
题目:88. Merge Sorted Array 思路: 这题很直观的可以看出由于两个数组都是排好序的,我们只需要从头到尾或从尾到头同时扫描两个数组,对比扫描到的值,取较大或较小的一个往第一个数组中摆放。把第二个数组合并进第一个数组既可以从前往后比较每次插入比较小的值到第一个数组中,也可以从后往前比较每次把较大...