来自专栏 · LeetCode Description Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively.You may assume that nums1 has enough space (size that is greater or equal...
Given two sorted integer arraysnums1andnums2, mergenums2intonums1as one sorted array. Note: You may assume thatnums1has enough space (size that is greater or equal tom+n) to hold additional elements fromnums2. The number of elements initialized innums1andnums2aremandnrespectively. 这道题很...
代码(Python3) class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ # i/j 分别表示 nums1/nums2 中还未使用的最大数的下标 i, j = m - 1, n - 1 # k 表示 nums...
The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ...
按照归并排序的惯性思路,因为归并排序中给定的是一个数组的两个区间,所以通常情况下会借助O(n)大小的辅助空间。思路如下: class Solution { public: void merge(int A[], int m, int B[], int n) { int temp[m+n]; int i = 0, j = 0, t = 0; ...
Leetcode No.88 Merge Sorted Array(c++实现) 1. 题目 1.1 英文题目 You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively. ...
classSolution{publicvoidmerge(int[]nums1,intm,int[]nums2,intn){if(nums1.length==0||nums2.length==0){return;}if(m==0){for(intk=0;k<n;k++){nums1[k]=nums2[k];}return;}int[]tnums=Arrays.copyOfRange(nums1,0,m);booleanflag;inti=0;intj=0;intk=0;for(;k<m+n;k++){flag...
Memory Usage: 13.2 MB, less than 46.71% of Python3 online submissions for Merge Sorted Array. sample 16 ms submission: NOTE: 从右往左对比"假·nums1"和"nums2",覆盖"真·nums1"的最右 classSolution:defmerge(self,nums1,m:int,nums2,n:int)->None:""" ...
博客分类: LeetCode随记面试切题 题目描述: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 新建一个...
主要体现一个倒着复制的思想,在c语言自带排序源码包里就有不少倒着复制的思想。 代码: java: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{publicvoidmerge(int[]nums1,int m,int[]nums2,int n){int i=m-1,j=n-1,k=m+n-1;while(i>=0&&j>=0)nums1[k--]=nums1[i]>=...