}if( result.get(k-1).end < intervals.get(len-1).start ) result.add(intervals.get(len-1));returnresult; } } 然后发现别人的答案中,有一个很难发现的细节,就是如果将start和end分别放入两个数组中,再进行排序,最后的结果与直接将intervals排序得到的结果一样,而这样做的话,
我的代码: 1classSolution {2publicList<Interval> merge(List<Interval>intervals) {3Collections.sort(intervals,newMyComparator());45for(inti = 0; i < intervals.size() - 1; i++) {6if(intervals.get(i).end >= intervals.get(i+1).start) {7intervals.get(i).end = intervals.get(i).end ...
Can you solve this real interview question? Merge Intervals - Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input
if(intervals == null || intervals.size() < 2) return intervals; List<Interval> res = new ArrayList<>(); int len = intervals.size(); int[] starts = new int[len], ends = new int[len]; for(int i = 0; i < len; i++){ starts[i] = intervals.get(i).start; ends[i] = in...
视频讲解 622:17 Leetcode力扣 1-300题视频讲解合集|手画图解版+代码【持续更新ing】 87万 803 视频 爱学习的饲养员 排序法 Python3版本 Java版本 其他版本本文为我原创本文禁止转载或摘编 计算机 程序员 编程 算法 数据结构 Python Java Leetcode 力扣...
LeetCode Top 100 Liked Questions 56. Merge Intervals (Java版; Medium) 题目描述 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] ...
【Leetcode】Merge Intervals https://leetcode.com/problems/merge-intervals/ 题目: Given a collection of intervals, merge all overlapping intervals. For example, Given[1,3],[2,6],[8,10],[15,18], return[1,6],[8,10],[15,18].
javapublic class Solution { public List<Interval> merge(List<Interval> intervals) { List<Interval> result = new ArrayList<Interval>(); Comparator<Interval> comparator = new Comparator<Interval>() { @Override public int compare(Interval o1, Interval o2) { ...
curEnd = intervals.get(i).end; } } result.add(new Interval(curStart, curEnd)); return result; } } 因为目前的实现已经支持java 8了,如果我们再运用一点lambda表达式语法的技巧, 代码可以更加简略一点: public class Solution { public List<Interval> merge(List<Interval> intervals) { ...
合并区间,是接下来插入区间的姊妹篇,由于LeetCode和Newcoder上分别要求用数组 和 动态数组实现 如下: 1.数组: class Solution { public int[][] merge(int[][] intervals) { if(intervals.length == 0) return new int[0][]; Arrays.sort(intervals, new Comparator<int[]>(){ public int compare(int...