我的代码: 1classSolution {2publicList<Interval> merge(List<Interval>intervals) {3Collections.sort(intervals,newMyComparator());45for(inti = 0; i < intervals.size() - 1; i++) {6if(intervals.get(i).end >= intervals.
public List<Interval> merge2(List<Interval> intervals) { if(intervals == null || intervals.size() < 2) return intervals; List<Interval> res = new ArrayList<>(); int len = intervals.size(); int[] starts = new int[len], ends = new int[len]; for(int i = 0; i < len; i++)...
}if( result.get(k-1).end < intervals.get(len-1).start ) result.add(intervals.get(len-1));returnresult; } } 然后发现别人的答案中,有一个很难发现的细节,就是如果将start和end分别放入两个数组中,再进行排序,最后的结果与直接将intervals排序得到的结果一样,而这样做的话,就直接达到了最快。其实...
其一,for循环不要用for (a: A)的形式,会出现ConcurrentModificationException的编译错误,文档是这样解释的:it is not generally permissible for one thread to modify a Collection while another thread is iterating over it. 其二,对intervals的cur元素进行删除操作之后,对应的indexi要减去1。 Solution Update 20...
LeetCode Top 100 Liked Questions 56. Merge Intervals (Java版; Medium) 题目描述 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] ...
Can you solve this real interview question? Merge Intervals - Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input
【Leetcode】Merge Intervals https://leetcode.com/problems/merge-intervals/ 题目: Given a collection of intervals, merge all overlapping intervals. For example, Given[1,3],[2,6],[8,10],[15,18], return[1,6],[8,10],[15,18].
[leetcode] Merge Intervals | 带overlap的interval数组,把overlap那些都merge了。 今天又被assign了不归我的活,怒了。干脆上班不工作了,直接刷题。 Given a collection of intervals, merge all overlapping intervals. For example, Given[2,6],[1,3],[8,10],[15,18],...
Can you solve this real interview question? Merge Intervals - Given an array of intervals where intervals[i] = [starti, endi], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input
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