1 Linked List 和 Python 基础操作 1.1 链表原理 1.2 链表的操作:增删查改 1.3 链表 in Python 2 LeetCode 21 合并两个有序链表 2.1 读题 2.2 完整的代码实现(包括了前面的结点定义、数组和链表转换函数) 时间复杂度分析 空间复杂度分析 考虑空列表的代码改进 2.3 解法二:递归 时间复杂度分析 空间
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 翻译: 合并两个有序链表并返回一个新的链表,新链表必须由前两个链表拼接...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 因为没有空间要求,所以想到ListNode*head = new ListNode(INT_MIN);重新定义一...
需要遍历 list2 中的全部 O(|list2|) 个结点 空间复杂度:O(1) 只需要维护常数个额外变量 代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 1. 2. # Definition for singly-linked list. ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目:合并两个单链表 思路:先比较两个各链表第一个节点,大的那个节点先设为合并的链表第一个节点,这样就找到了要合成的链表的节点了。
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1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list ...
21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题意:合并两个原本有序的列表 c++代码: /// main.cpp// LeetCode/// Created by linSir on 2017/9/5.// Copyright...
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