std(v), values), " ")) print "sum %s" % (string.join( map(lambda v: options.value_format % reduce( lambda x,y: x+y, v), values), " ")) print "q1 %s" % (string.join( map(lambda v: options.value_format % scipy.stats.scoreatpercentile(v,per=25), values), " ")) ...
The standard deviation of a normal distribution is 12 and 90% of the values are greater than 6. What is the value of the mean? Given a normal distribution with a standard deviation of 10, what is the mean if 21% of the values are ...