if(sum!=0&& max_cir == 0 ) return max_nor ; 使用这个判断, 如果都被舍弃,则直接使用第一种情况的结果。 完整代码如下: class Solution { public: int maxSubarraySumCircular(vector<int>& A) { vector<int> pre_sum; int sum = 0; int max_nor= maxSubArray(A); for(int i = A.size(...
1classSolution2{3public:4intmaxSumCycle(vector<int>&vec,int&left,int&right)5{6intmaxsum = INT_MIN, curMaxSum =0;7intminsum = INT_MAX, curMinSum =0;8intsum =0;9intbegin_max =0, begin_min =0;10intminLeft, minRight;11for(inti =0; i < vec.size(); i++)12{13sum +=vec...
LC 918. Maximum Sum Circular Subarray link classSolution {public:intmaxSubarraySumCircular(vector<int>&A) {intmaxsum=INT_MIN;intminsum=INT_MAX;inttotal=0;intcurmax=0;intcurmin=0;for(inti=0;i<A.size();i++){ curmax=max(curmax+A[i],A[i]); curmin=min(curmin+A[i],A[i]); ...
classSolution:defmaxSubarraySumCircular(self, A:List[int]) ->int: cur_min, cur_max, max_sum, min_sum, total =0,0, -pow(10,10),pow(10,10),0fornuminA: cur_max =max(cur_max+num, num) max_sum =max(max_sum, cur_max) cur_min =min(cur_min+num, num) min_sum =min(min_sum...
classSolution {public:intmaxSubarraySumCircular(vector<int>&A) {inttotal =0;intcurmax =0, maxsum =INT32_MIN;intcurmin =0, minsum =INT32_MAX;for(inta : A) { curmax= max(curmax +a, a); maxsum=max(maxsum, curmax); curmin= min(curmin +a, a); ...
Given acircular integer arraynums of length n, returnthe maximum possible sum of a non-emptysubarrayofnums. Acircular arraymeans the end of the array connects to the beginning of the array. Formally, the next element of nums[i] is nums[(i + 1) % n] and the previous element of nums...
=max(Max(A[i]), sum-sum)=0 含义为:Max subarray为空数组。 显然不满足题意。 因此,在这种情况下,我们要求的最大和,只能是Max(A[i])=allMax 代码参考: 1classSolution {2public:3intmaxSubarraySumCircular(vector<int>&A) {4intsum=A[0];5intcurMax=A[0], curMin=A[0], allMax=A[0], ...
1 class Solution { 2 func maxSubarraySumCircular(_ A: [Int]) -> Int { 3 4 var maxSum = A.max()! 5 6 var simpleA: [Int] = [] 7 simpleA.reserveCapacity(A.count) 8 var isPos = A.first! > 0 9 var sum = 0 10 for i in 0..<A.count { 11 if A[i] > 0 || A[...
1classSolution {2publicintmaxSubarraySumCircular(int[] nums) {3inttotal = 0;4//全局的最大值5intmaxSum = nums[0];6//当前的最大值7intcurMax = 0;8//全局的最小值9intminSum = nums[0];10//当前的最小值11intcurMin = 0;12for(intnum : nums) {13curMax = Math.max(curMax +num,...
二、Maximum Sum Circular Subarray 问题描述: 问题求解: 唯一的边界条件是如果全部为负数,那么minsubarray = sum,这个时候直接返回max即可。 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 public int maxSubarraySumCircular(int[] A) { int n = A.length; int sum = 0; for (int...