LeetCode - The World's Leading Online Programming Learning Platformleetcode.com/problems/maximum-gcd-sum-of-a-subarray/description/ 简单介绍一下题目大意,更详细的描述可以见链接中的原题描述及样例数据: 给定一个长度为n的正整数数组nums。对于nums
0: dp[i-1]; and clearly, we need a global variable to keep record of the global maximum. so the code will be: classSolution{publicintmaxSubArray(int[] nums){if(nums==null|| nums.length ==0)return0;int[] dp =newint[nums.length]; dp[0] = nums[0];intres=dp[0];for(inti=1;...
dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i-1]<0 we can just choose not to add it. so the...
Input: [-2,-3,-1] Output: -1 Explanation: Subarray [-1] has maximum sum -1 Note: -30000 <= A[i] <= 30000 1 <= A.length <= 30000 这道题比较好理解,关于最大子数组的解法 可以参考 int maxSubArray(vector<int>& A) { int ans = INT_MIN; int cur = INT_MIN; for (int k ...
Maximum sum subarrayAlgorithm designGiven a sequence of n real numbers and an integer parameter k, the problem studied in this paper is to compute k subsequences of consecutive elements with the sums of their elements being the largest, the second largest, …, and the kth largest among all ...
return the maximum sum for a non-empty subarray (contiguous elements) with at most one element deletion. In other words, you want to choose a subarray and optionally delete one element from it so that there is still at least one element left and the sum of the remaining elements is maximu...
Leetcode刷题 152.乘积最大子序列 Maximum Product Subarray 12:13 Leetcode刷题 349.两个数组的交集 Intersection of Two Arrays 06:07 Leetcode刷题 219.存在重复元素 II Contains Duplicate II 04:57 Leetcode刷题 66.加一 Plus one 05:50 Leetcode刷题 53.最大子序和 Maximum Subarray 10:21 ...
lintcode: Maximum Subarray Given an array of integers, find a contiguous subarray which has the largest sum. Challenge Can you do it in time complexity O(n)? sumSub[i]表示以第i个数结尾的子数组的最大和,则 sumSub初始化为nums; sumSub[i]= sumSub[i-1]+nums[i]>sumSub[i]?(sumSub[i...
LeetCode刷题日记 Day 28 Part 2 - Maximum Product Subarray, 视频播放量 70、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 blackwoodkane, 作者简介 ,相关视频:LeetCode刷题日记 Day 11 Part 2 - Unique Paths,LeetCode刷题日记 Day 24 Part 1
Your task is to reverse such a subarray that the sum of elements on even positions of the resulting array is maximized (i. e. the sum of elements a0,a2,…,a2k for integer k=⌊n−12⌋ should be maximum possible). You have to answer t independent test cases. Input The first ...