问题简介 本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续子数组。比如,数组 A = [-2, -3, 4, -1, -2…
//A Divide and Conquer based program for maximum subarray sum problem#include <stdio.h>#include<limits.h>//A utility funtion to find maximum of two integersintmax(inta,intb) {return(a > b)?a : b; }//A utility funtion to find maximum of three integersintmax(inta,intb,intc) {return...
设prefix为前缀和,设i < j,一般都是通过算sum = prefix[j] - prefix[i]求和的最大值,但是本题中有取模,要求sum最大。 第一种情况:如果prefix[j] > prefix[i],sum < prefix[j],这种情况就不需要考虑了。 第二种情况:prefix[j] < prefix[i],又i < j,那么prefix[j]是取模后得到的值,此时sum ...
本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续...
---> i - map.get(sum - k)在这个例子里就是5-2 代码如下: public int maxSubArrayLen(int[] nums, int k) { int sum = 0, max = 0; HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); for (int i = 0; i < nums.length; i++) { sum = sum + nums[i]; if ...
problem: Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray [4,−1,2,1] has the largest sum = 6. ...
Notice:The subarray should contain at least one number. 给定一个整数数组,找到一个具有最大和的子数组,返回其最大和。 注意:子数组最少包含一个数 【题目链接】 http://www.lintcode.com/en/problem/maximum-subarray/ 【题目解析】 O(n)就是一维DP. ...
I am getting WA on test 28 ofthisproblem. Would really appreciate all the help. My Approach Basically, I am partitioning each segment[l…r][l…r]into three partitions,p1,p2,p3p1,p2,p3where p2p2= maximum subarray sum in[l…r][l…r] ...
(5kyu) The maximum sum subarray problem consists in finding the maximum sum of a contiguous subsequence in an array or list of integers: maxSequence([-2 , 1, -3, 4, -1 , 2, 1, -5, 4]) # should be 6: [4, -1, 2, 1] ...
本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续子数组。比如,数组 A = [-2, -3, 4, -1, -2, 1, 5, -3], 最大子数组应为[4, -1, -2, 1, 5],其和为7。 首先,如果...