I was thinking to try something like the solution of GSS3Link to the problem... The idea is to save the answer for a suffix and a prefix subaaray for particular segment and also saving the subarray with maximum( sum* length) for that segemnt. Then keep merging them to get the answer...
p2p2= maximum subarray sum in[l…r][l…r] p1p1= remaining left side sum p3p3= remaining right side sum p1+p2+p3=∑a[l…r]p1+p2+p3=∑a[l…r] Now to combine two arrays, the maximum subarray sum of the combined array would bemax(p(1)2,p(2)2,p(1)2+p(1)3+p(2)1+p(...
2019-12-16 16:22 − [题目](https://leetcode.com/problems/maximum-side-length-of-a-square-with-sum-less-than-or-equal-to-threshold/) 我是按照边进行二分的 ``` class Solution { public: ... Shendu.CC 0 327 Codeforces 547C/548E - Mike and Foam 题解 2019-12-19 21:57 −...
Codeforces 1107G Vasya and Maximum Profit [单调栈] 洛谷Codeforces 我竟然能在有生之年踩标算. 思路 首先考虑暴力:枚举左右端点直接计算. 考虑记录\(sum_x=\sum_{i=1}^x c_i\),设选\([l,r]\)时那个奇怪东西的平方为\(f(l,r)\),使劲推式子: \[ ans_{l,r}=(r-l+1)\times a-sum_r+su...
Given an array, we need to find two subarrays with a specific length K such that sum of these subarrays is maximum among all possible choices of subarrays. arr size <10^5 n<10^3 Examples: Input : arr[] = [2, 5, 1, 2, 7, 3, 0] ...
Find all maximum sub-array in which all pairs have their sum >= k. I feel it can be solved using monotonic queue likethis solution, but i am not able to think correct answer. Please give some hints. e.g. Array :[ 1 5 2 3 6 5 4 2 2 8 ] and K = 8 ...
I found onewithO(n log n)3.Findthe largestsub-array which elements_sumisdivisiblebya number QSolution:O(n)Solutionexists.[here](http://stackoverflow.com/questions/16605991/number-of-subarrays-divisible-by-k?rq=1)4.Findthe largestsub-sequences which elements form an arithmetic progression/...
Given an array of size n,for each k from 1 to n, find the maximum sum of contiguous subarray of size k. This problem has an obvious solution with time complexity O(N2) and O(1) space. Lua code: array = {7, 1, 3, 1, 4, 5, 1, 3, 6} ...
partition the array into exactly K subarrays and calculate their sum. find the minimum possible difference of the maximum sum and the minimum sum. (1<k<=n<=40) for example for N=6 and K=3 and array={5 1 1 1 3 2} the optimal way is to split it into [5][1 1 1][3 2] so...
Here's a solution: First, we'll look at it from a different angle: we need to choosekdistinct subarrays (continuous), taking a total of the whole array, so that the gcd of all the subarray sums is maximal. Now, by this observation, we can see that since all the subarrays' sums ...