path maximum sum querytreeLet T be a node-weighted tree with n nodes, and let π(u, v) denote the path between two nodes u and v in T. We address two problems: (i) Path Maximum Query: Preprocess T so that, for a
The path may start and end at any node in the tree. For example: Given the below binary tree, 1 / \ 2 3 Return 6. 解题思路,递归 a b c curmax = max (a+b, a, a+c) //计算当前节点单边最大值, 如果a+b 最大,那就是说,把左子树包含进来,有利可图 如果a+c 最大,把右子树包含...
* };*/classSolution {public:intmaxPathSum(TreeNode *root) { maxPathSumCore(root);returnMAX; }intmaxPathSumCore(TreeNode *node) {if(NULL == node)return0;inta = maxPathSumCore(node ->left);intb = maxPathSumCore(node ->right);if((a+b+node->val) > MAX) MAX = (a+b+node->v...
Question: By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23. 3 74 246 8 593 That is, 3 + 7 + 4 + 9 = 23. 从下面三角形的顶部开始,移动到下面一行的相邻数字,从上到下的最大值是23。 Find the...
Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path does not need to go through the root. ...
public int maxPathSum(TreeNode root) { if (root == null) { return Integer.MIN_VALUE; } //左子树的最大值 int left = maxPathSum(root.left); //右子树的最大值 int right = maxPathSum(root.right); //再考虑包含根节点的最大值 int all = ...; return Math.max(Math.max(left, right...
Binary Tree Maximum Path Sum 最近忙着水论文,好久没刷题了,现在真是看到论文就烦啊,来刷刷题。 返回最大值,这题需要注意的是,在递归的时候不能返回最大值,只能返回单向的值,最大值每次保留即可。 int maxPathSum(TreeNode *root) { max_sum = INT_MIN;...
LintCode 94. Binary Tree Maximum Path Sum Description Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. Example Given the below binary tree: 1 / \ 2 3 return 6. 解题 题意是找到整棵树中,值最大的一条路径。
http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。 ** 总结: pre-order -> top-down post-order -> bottom-up in-order -> ? level-order -> bfs ...
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