Can you solve this real interview question? Maximum Value of a String in an Array - The value of an alphanumeric string can be defined as: * The numeric representation of the string in base 10, if it comprises of digits only. * The length of the strin
Given a non-empty array of numbers, a0, a1, a2, … , an-1, where 0 ≤ ai < 231. Find the maximum result of ai XOR aj, where 0 ≤ i, j < n. Could you do this in O(n) runtime? Example: Input: [3, 10, 5, 25, 2, 8] Output: 28 Explanation: The maximum result is ...
Github 同步地址: https://github.com/grandyang/leetcode/issues/421 参考资料: https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/ https://leetcode.com/problems/maximum-xor-of-two-numbers-in-an-array/discuss/130427/()-92 https://leetcode.com/problems/maximum-xor-of-two-...
[LeetCode] 421. Maximum XOR of Two Numbers in an Array Given an integer array nums, return the maximum result of nums[i] XOR nums[j], where 0 <= i <= j < n. Example 1: Input: nums = [3,10,5,25,2,8] Output: 28 Explanation: The maximum result is 5 XOR 25 = 28. Exampl...
13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 参考文献 [LeetCode] Maximum XOR of Two Numbers in an Array 数组中异或值最大的两个数字【特别好】【位运算】maximum-xor-of-two-numbers-in-an-array
Can you solve this real interview question? Get Maximum in Generated Array - You are given an integer n. A 0-indexed integer array nums of length n + 1 is generated in the following way: * nums[0] = 0 * nums[1] = 1 * nums[2 * i] = nums[i] when 2 <= 2
leetcode根本不让你通过的,比如100个数据100^100次循环 天知道要跑多久。 神奇的Kadane's algorithm 代码 class Solution: def maxSubArray(self, nums: List[int]) -> int: max_current = max_global = nums[0] for num in nums[1:]: max_current = max(num,max_current+num) if(max_current...
LeetCode 152. Maximum Product Subarray 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode 1 人赞同了该文章 Description Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1...
421 Maximum XOR of Two Numbers in an Array 数组中两个数的最大异或值 Description: Given an integer array nums, return the maximum result of nums[i] XOR nums[j], where 0 ≤ i ≤ j < n. Follow up: Could you do this in O(n) runtime?
1. Description Get Maximum in Generated Array 2. Solution Version 1 classSolution:defgetMaximumGenerated(self,n:int)->int:ifn==0:return0ifn==1:return1maximum=1nums=[0for_inrange(n+1)]nums[1]=1forkinrange(2,n+1):i=k//2ifk%2==0:nums[k]=nums[i]else:nums[k]=nums[i]+nums[...