Can you solve this real interview question? Maximum Element After Decreasing and Rearranging - You are given an array of positive integers arr. Perform some operations (possibly none) on arr so that it satisfies these conditions: * The value of the fir
You are given a0-indexedarraynumscomprising ofnnnon-negative integers. In one operation, you must: Choose an integeriisuch that1≤i<n1≤i<nandnums[i]>0nums[i]>0. Decreasenums[i]nums[i]by11. Increasenums[i−1]nums[i−1]by11. Return theminimumpossible value of themaximuminteger ofn...
Given an arraynums, there is a sliding window of sizekwhich is moving from the very left of the array to the very right. You can only see theknumbers in the window. Each time the sliding window moves right by one position. Return the max sliding window. Example: [1,3,-1,-3,5,3...
Yes, it is. according to leetcode, every element is processed exactly twice(which is added and removed from deque) and besides, this solution must be better than solutions using priority queue, since we can build heap in O(K), and each time we need to delete and insert a node, which ...
918. Maximum Sum Circular Subarray # 题目 # Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Fo
Monotonic Queue is getting more popular, and finally LeetCode put it on. Typical Solution: element in array will be pushed\popped in\from a sorted data structure, which points to multiset(or any heap-like data structure). Complexity is O(nlgn). ...
https://leetcode.com/problems/sliding-window-maximum/ Given an array nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position....
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Solution DP, time O(n), space O(1) This is very similar to the " max cumulative sum subarray" problem. here you keep 2 values: the max cumulative product UP TO current element starting from SOMEWHERE in the past, and the minimum cumuliative product UP TO current element . it would be...