Here's a solution: First, we'll look at it from a different angle: we need to choosekdistinct subarrays (continuous), taking a total of the whole array, so that the gcd of all the subarray sums is maximal. Now,
Input: First line contains N (2<=N<=10^5). Next line contains N numbers, each of them more than 1 and less than 10^5, output: Output the largest GCD of any pair of numbers. You can iterate over all possible gcds and for each check if there exist two or more numbers divisable ...
Codeforces Round #651 (Div. 2) A. Maximum GCD (思维) 题意:在11~nn中找两个不相等的数使得他们的gcdgcd最大. 题解:水题,如果nn是偶数,那么一定取nn和n/2n/2,nn是奇数的话,取n−1n−1和(n−1)/2(n−1)/2. 代码: #include<iostream>#include<cstdio>#include<cstring>#include<cmath...
Codeforces Round #651 (Div. 2) A Maximum GCD、B GCD Compression、C Number Game、D Odd-Even Subsequence A. Maximum GCD 题意: t组输入,然后输入一个n,让你在区间[1,n]之间找出来两个不相等的数a,b。求出来gcd(a,b)(也就是a,b最大公约数)。让你求出来最大的gcd(a,b)是多少。 题解: 最...
Codeforces Round #651 (Div. 2) A Maximum GCD、B GCD Compression、C Number Game、D Odd-Even Subsequence,A.MaximumGCD题意:t组输入,然后输入一个n,让你在区间[1,n]之间找出来两个不相等的数a,b。求出来gcd(a,b)(也就是a,b最大公约数)。让你求出来最大的gcd(a,
Find the maximum possible value ofgcd(a1,a2,…,an)+gcd(b1,b2,…,bn)\gcd(a_1, a_2, \ldots, a_n) + \gcd(b_1, b_2, \ldots, b_n)gcd(a1,a2,…,an)+gcd(b1,b2,…,bn)that you can get by paying in total at mostdddcoins for swapping some ...
codeforce-1092-F.TreewithMaximumCost-树上换根【Description】 【Input】 【Output】 【Examples】 SampleInputSampleOutputSampleInputSampleOutput【ProblemDescription】 【Solution】 【Code】 智能推荐 【Codeforces Round #551(Div. 2)】Serval and Rooted Tree(思维+dp) ...
CodeForces Algorithms. Contribute to m-aprameya/CodeForces development by creating an account on GitHub.
给你n 个数字 A_i ,有一个操作:任选一个数字将其+1,你可以进行这个操作至多 K 次(可以不操作),问如何使得这 n 个数的GCD最大。 Here_SDUT 2022/09/19 3070 Code Forces 149DColoring Brackets(区间DP) 编程算法数据结构 Coloring Brackets time limit per test 2 seconds memory limit pe...
There can be onlydifferent gcd values among suffixes of an array (due to Euclide's algorithm complexity). So you can add characters one by one keeping all possible gcd's of current array's suffixes. By the way, does anyone know solution for the original problem now, 2 years later?