设dp[i]代表以a[i]结尾的连续上升子序列中元素的个数,那么dp[i] = (a[i] > a[i - 1] ? dp[i - 1] + 1 : 1),含义是如果a[i]比a[i-1]大,那么a[i]可以加入到以a[i-1]为尾的最长连续上升子序列末尾,取代a[i-1]成为新的末尾,原本的长度加1。否则a[i]单独作为一个子序列,长度为1。然后找到这个数组的最大
#P702A. Maximum Increase Description You are given array consisting ofnintegers. Your task is to find the maximum length of an increasing subarray of the given array. A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarrays...
题意:给定 n 个数,问你连续的最长的序列是几个。 析:从头扫一遍即可。 代码如下: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 #include <cstdio> #include <string> #include <cstdlib> #...
A. Maximum Increase time limit per test memory limit per test input output n strictly greater Input n(1 ≤ n ≤ 105) — the number of integers. npositive integersa1, a2, ..., an(1 ≤ ai ≤ 109). Output Print the maximum length of an increasing subarray of...
Educational Codeforces Round 15 A. Maximum Increase bfsof 一只退役蒟蒻ACMer(考研备考) 来自专栏 · Codeforces题解 创作声明: 内容包含剧透 1 人赞同了该文章 模拟记录一下就行了,大水题 #include <bits/stdc++.h> using namespace std; int main() { int t; cin>>t; int arr[t],cnt=1,ans=0;...
Increase maximum code size? 64kb is great, but often isn't enough for libraries with complex data structures. This isn't a huge issue in Java or C++ which have phenomenal standard libs, but much more of an issue in things like Rust, Go, or JS which really rely on importing libraries ...
Codeforces702A - Maximum Increase【尺取】 #include 题意: 求一个连续的最长子序列长度; 思路: 没看仔细还wa1了…以为LIS… 然后写了尺取吧。。。= =太不仔细了。不过收获是LIS特么写挫了然后看了学长的blog<-点我… 题目的挫code… #include <iostream>...
(n) way to do that but it seems i cant find one (think about a greedy strategy which moves from left to right and increase cnt whent the current sum is >=min and reset sum to 0. but it does not work the cnt>k because its not certain that we can split something and keep the ...
0 条题解Maximum Increase 查看题目 登录后递交 讨论 题解 文件 统计 信息 ID 4839 时间 1000ms 内存 256MiB 难度 (无) 标签 dp greedy implementation *800 递交数 0 已通过 0 上传者 root 关于 联系我们 隐私 服务条款 Language Theme 京ICP备2021032661号-1 京公网安备 11011102002149号 © ...
CodeForces 702A Maximum Increase 简单dpdp。如果a[i]>a[i−1]a[i]>a[i−1],那么dp[i]=dp[i−1]+1dp[i]=dp[i−1]+1。否则,dp[i]=1dp[i]=1。答案为dp[i]dp[i]中的最大值。#pragma comment(linker, "/STACK:1024000000,1024000000") #include...