Given the root of a binary tree, return its maximum depth.A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 英文版地址 leetcode.com/problems/m 中文版描述 给定一个二叉树,找出其最大深度。二叉树的深度为根节点到...
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree[3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its depth = 3. 求二叉树的最大深度问...
题目描述 求给定二叉树的最大深度, 最大深度是指树的根结点到最远叶子结点的最长路径上结点的数量。 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longe
clone()), Self::max_depth(root.borrow().right.clone()), ) } else { // 如果根结点不存在,则返回 0 0 } } } 题目链接: Maximum Depth of Binary Tree : leetcode.com/problems/m 二叉树的最大深度: leetcode-cn.com/problem LeetCode 日更第 31 天,感谢阅读至此的你 欢迎点赞、收藏、在...
Maximum Depth of Binary Tree code 递归方法 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
LeetCode Maximum Depth of Binary Tree (求树的深度),题意:给一棵二叉树,求其深度。思路:递归比较简洁,先求左子树深度,再求右子树深度,比较其结果,返回:max_one+1。1/**2*Definitionforabinarytreenode.3*structTreeNode{4*intval;5...
英文coding面试练习 day3-1 | Leetcode662 Maximum Width of Binary Tree, 视频播放量 29、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 Rollwithlife, 作者简介 To remember,相关视频:英文coding面试练习 day3-2 | Leetcode907 Sum of Subarray
Given a n-ary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value...
用两个栈的方法很巧妙。同时暂存头结点的depth -> temp BFS My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * }
http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。 ** 总结: pre-order -> top-down post-order -> bottom-up in-order -> ? level-order -> bfs ...