Hello Codeforces. Recently I faced a problem which I couldn't solve in an hour. It is as follows: Max Sum Subarray of atleast 2 numbers. Of course, for just max sum subarray it is Kadane's algorithm in O(n) time, however, I couldn't think of a way to solve for atleast 2 numb...
MaxSubArraySum是一种经典的算法问题,其目标是在给定的整数数组中找到具有最大总和的连续子数组。解决这个问题的常见方法是使用动态规划。算法的基本思想是维护两个变量:当前子数组的最大和以及全局最大和。在遍历数组时,我们不断更新当前子数组的最大和,如果该和变得小于0,则重新开始计算子数组和,并更新全局最大和...
Also, subset of consecutive elements is probably better defined as subarray. avidcoder:2017-08-15 09:11:39 Weak test cases! Since it is a tutorial problem. It's okay. Last edit: 2017-08-15 09:33:11 Francky:2014-12-28 16:33:34 ...
maximum contiguous sum in the given array. */ // Package maxsubarraysum is a package containing a solution to a common // problem of finding max contiguous sum within a array of ints. package maxsubarraysum import ( "github.com/TheAlgorithms/Go/math/max" ) // MaxSubarraySum returns the...
sum; } max_subarray; max_subarray find_maximum_subarray(int A[], unsigned low, unsigned high) { max_subarray suffixes[high - low]; suffixes[0].left = low; suffixes[0].right = low + 1; suffixes[0].sum = A[low]; for (int ...
st.insert(curSum); } } }returnres; } }; Github 同步地址: https://github.com/grandyang/leetcode/issues/363 类似题目: Maximum Subarray Range Sum Query 2D - Immutable Maximum Size Subarray Sum Equals k 参考资料: https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-k/ ...
https://en.wikipedia.org/wiki/Maximum_subarray_problem 乍一看这个要比最大子段和高级,似乎要枚举最大字串的右边界i和中间点center,但其实只用枚举右边界i,右边界从i-1变成i之后,中间点只可能是center或者i-1中的一个,中间点为center的时候左边界不变最优,中间点为i-1的时候需要求最优左边界(这就是个内...
Given an array, a window must be chosen such that this component (sum(a[i] + a[i+1] + a[i+2] ... a[j])* (j-i+1) is maximized where i and j are indices and i<j and the component value must be equal or less than the threshold . (sum(a[i] + a[i+1] + a[i+2...
classSolution{publicintmaxSumSubmatrix(int[][]matrix,intk){//2D Kadane's algorithm + 1D maxSum problem with sum limit k//2D subarray sum solution//boundary checkif(matrix.length==0)return0;intm=matrix.length,n=matrix[0].length;intresult=Integer.MIN_VALUE;//outer loop should use smaller...
importjava.util.*;publicclassKmaxsum{staticvoidmax_average_k_numbers(intn,intk,intm,int[]arr,int[]query){doublemax_avg=0.0;PriorityQueue<Integer>pq=newPriorityQueue<Integer>();Arrays.sort(arr);doublesum=0;for(inti=n-1;i>=n-k;i--){pq.add(arr[i]);sum=sum+arr[i];}for(inti=0;i...