解答不需要数组。 classSolution {public:intmaxSubArray(vector<int>&nums) {//明显的动态规划,因为是连续的,所以这个子序列:1.取前面和后面的元素则和变小,//比如,如果4,左边的dp(取该元素)是依次[-2,1,-2,4,3,5,6,1,5][]if(nums.empty())return0; vector<int>vec; vec.push_back(nums[0])...
以及这道题目:max subarray sum no more than k 本题基本上是以上两种思路的组合了,具体的实现很简单。 题目描述 Given a non-empty 2D matrix matrix and an integer k, find the max sum of a rectangle in the matrix such that its sum is no larger than k. ...
这个问题是这样的(https://leetcode.com/problems/maximum-subarray/): Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. 就是给一组整数,找到一组连续的子序列,让子序列的和最大,并且返回最大和。 比如说: 输入...
Maximum Subarray Range Sum Query 2D - Immutable Maximum Size Subarray Sum Equals k 参考资料: https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-k/ https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-k/discuss/83618/2-Accepted-Java-Solution https://leetcode.com...
Leetcode之Maximum Subarray 问题 问题描述: Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] ......
First thing to note is that sum of subarray(i,j]is just the sum of the firstj elements less the sum of the firsti elements. Store these cumulative sums in the array cum. Then the problem reduces to findingi,j such thati<j andcum[j]−cum[i] is as close tokbut lower than it....
package max_subarrayy; import java.lang.Math; public class max_subarrayy { private static int[] array; public static class mark{ private int lom = 100; private int him; private int value; public mark(int a,int b,int c){ lom = a;him = b;value = c; ...
https://www.quora.com/Given-an-array-of-integers-A-and-an-integer-k-find-a-subarray-that-contains-the-largest-sum-subject-to-a-constraint-that-the-sum-is-less-than-k time complexity: O(n log n) space: O(n) 我需要一个 TreeSet 的配合。
本题和560. Subarray Sum Equals K非常类似,数组中有负数并不影响。 classSolution {public:intmaxSumSubmatrix(vector<vector<int>>& matrix,intk) {intm=matrix.size(), n=m==0?0:matrix[0].size();if(m==0|| n==0)return0;intres=INT_MIN;for(intr1=0;r1<m;++r1){ ...
0152-Maximum-Product-Subarray 0153-Find-Minimum-in-Rotated-Sorted-Array 0155-Min-Stack 0159-Longest-Substring-with-At-Most-Two-Distinct-Characters 0160-Intersection-of-Two-Linked-Lists 0161-One-Edit-Distance 0167-Two-Sum-II-Input-array-is-sorted 0169-Majority-Element 01...