02 第一种解法 使用一个记数变量count,for循环遍历nums中的元素,遇到1时count就自加1,遇到0时,比较最大值,count归零,循环结束后,如果count不等于0,还要再取一次最大值,最后返回最大值。 publicintfindMaxConsecutiveOnes(int[] nums){intresult = Integer.MIN_VALUE;intcount =0;for(inti=0; i<nums.length...
Time Complexity: O(nums.length). Space: O(1). AC Java: 1classSolution {2publicintfindMaxConsecutiveOnes(int[] nums) {3if(nums ==null|| nums.length == 0){4return0;5}67intres = 0;8intcount = 0;9intwalker = 0;10intrunner = 0;11while(runner <nums.length){12if(nums[runner++]...
3 LeetCode 485 3.1 题目 先上英文版的题目,再看中文版。 3.2 解法一:逐个元素判断 fromtypingimportListclassSolution:deffindMaxConsecutiveOnes(self,nums:List[int])->int:##注意这里是“List“,而不是”list“;ifnumsisNoneorlen(nums)==0:## 如果列表 lis 为空return0count=result=0## 计数变量,结果...
Max Consecutive Ones II 题目链接:https://leetcode.com/problems... public class Solution { public int findMaxConsecutiveOnes(int[] nums) { // 2 points, slide window int i = 0, j = 0; int global = 0; // count the number of flip int count = 0; while(j < nums.length) { if(n...
LeetCode485题目可以用动态规划解决吗? 题目 先来看一下题目: Given a binary array, find the maximum number of consecutive 1s in this >array. The input array will only contain 0 and 1. The length of input array is a positive integer and will not exceed 10,000 题目的翻译是:给定一个二进制...
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. 1. 2. 3. 4. 5. Note: The input array will only contain 0 and 1. The length of input array is a positive integer and will not exceed 10,000 ...
LeetCode-485. Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s....
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485. 最大连续 1 的个数 - 给定一个二进制数组 nums , 计算其中最大连续 1 的个数。 示例 1: 输入:nums = [1,1,0,1,1,1] 输出:3 解释:开头的两位和最后的三位都是连续 1 ,所以最大连续 1 的个数是 3. 示例 2: 输入:nums = [1,0,1,1,0,1] 输出:2 提示
0485-Max-Consecutive-Ones/cpp-0485 CMakeLists.txt main.cpp 0490-The-Maze 0494-Target-Sum 0497-Random-Point-in-Non-overlapping-Rectangles 0498-Diagonal-Traverse 0501-Find-Mode-in-Binary-Search-Tree 0509-Fibonacci-Number 0518-Coin-Change-2 0519-Random-Flip-Matrix 0528-...