题目地址:https://leetcode-cn.com/problems/max-consecutive-ones-ii/题目描述Given a binary array, find the maximum number of consecutive 1s in this array if you can flip at most one 0.Example 1:Input: [1,0,1,1,0] Output: 4 Explanation: Flip the first zero will get the the maximum ...
classSolution: deffindMaxConsecutiveOnes(self, nums:List[int])->int: maxCnt=0 lastCnt=-1 thisCnt=0 foriinrange(len(nums)): ifnums[i]==1: thisCnt+=1 else:# 0 maxCnt=max(maxCnt, lastCnt+1+thisCnt) lastCnt=thisCnt thisCnt=0 maxCnt=max(maxCnt, lastCnt+1+thisCnt) returnmaxCnt...
题目地址:https://leetcode-cn.com/problems/max-consecutive-ones-ii/ 题目描述 Given a binary array, find the maximum number of consecutive 1s in this array if you can flip at most one 0. Example 1: Input: [1,0,1,1,0] Output: 4 Explanation: Flip th...
1classSolution {2publicintfindMaxConsecutiveOnes(int[] nums) {3intmax = 0;4//保持queue中只有一个15//等价于滑动窗口找子串,子串内最多只能有一个16intk = 1;7Queue<Integer> zeroIndex =newLinkedList<>();8for(intl = 0, h = 0; h < nums.length; h++) {9if(nums[h] == 0) {10zer...
class Solution: def findMaxConsecutiveOnes(self, nums: List[int]) -> int: return max( map( len, ''.join(map(str, nums)).split('0') ) ) 时间复杂度:O(n),其中n是数组 nums 的长度。转换和分割操作的复杂度均为线性 空间复杂度:O(n),字符串连接和分割可能需要与原数组相同的空间 算法的...
def findMaxConsecutiveOnes(self, nums): """ :type nums: List[int] :rtype: int """ return len(max("".join(map(str, nums)).split("0"))) 别人解法思路: 设置两个计数器:结果值和计数值。以此访问list,如果值为1,计数值加一,结果值取结果值和计数值中的大值。如果值为0,计数值复为0。
Leetcode 1004 Max Consecutive Ones III Leetcode 1658 Minimum Operations to Reduce X to Zero 宽度优先搜索(BFS):面试中最常考的 基础知识: 常见的BFS用来解决什么问题?(1) 简单图(有向无向皆可)的最短路径长度,注意是长度而不是具体的路径(2)拓扑排序(3) 遍历一个图(或者树) BFS基本模板(需要记录层...
1004.Max-Consecutive-Ones-III (M) 1052.Grumpy-Bookstore-Owner (M) 1358.Number-of-Substrings-Containing-All-Three-Characters (M) 1838.Frequency-of-the-Most-Frequent-Element (H-) 395.Longest-Substring-with-At-Least-K-Repeating-Characters (H) 1763.Longest-Nice-Substring (H) 2009.Minimum-Numbe...
487 max-consecutive-ones-ii 🔒 📝 Medium 488 zuma-game Hard 489 kth-smallest-instructions Hard 490 the-maze 🔒 📝 Medium 491 increasing-subsequences Medium 492 construct-the-rectangle Easy 493 reverse-pairs 📝 Hard 494 target-sum 📝 Medium 495 teemo-attacking 📝 Easy 496 next-greate...
事情是这样的. 下面这个就是我在GitHub上面自动生成的LintCode表格. 当时先做的是LintCode, 大约有150来道。 现在转手来做LeetCode,作为复习和...