3 LeetCode 485 3.1 题目 先上英文版的题目,再看中文版。 3.2 解法一:逐个元素判断 fromtypingimportListclassSolution:deffindMaxConsecutiveOnes(self,nums:List[int])->int:##注意这里是“List“,而不是”list“;ifnumsisNoneorlen(nums)==0:## 如果列表 lis 为空return0count=result=0## 计数变量,结果...
Longest Consecutive Sequence (哈希表) LeetCode - 128. Longest Consecutive Sequence (哈希表) 题目链接 题目 解析 第一种方法: 使用一个HashSet来存储对应的值,一开始先将所有的值都加入set; 遍历数组的每一个元素,每次去检查当前元素num的前一个元素num - 1是不是在set中,如果是,说明num不是最长长度的...
【Code】关关的刷题日记21——Leetcode 485. Max Consecutive Ones 其他 关小刷刷题 21——Leetcode 485. Max Consecutive Ones 题目 Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits ...
1publicclassSolution {2publicintfindMaxConsecutiveOnes(int[] nums) {3int[] newNums =newint[nums.length+2];4newNums[0] = 0;5newNums[newNums.length-1] = 0;6for(inti = 1; i < newNums.length-1; i++) {7newNums[i] = nums[i-1];8}9intans = 0;10intlastPos = 0;11for(inti...
1、题目描述 2、问题分析 遍历一次数组,以每个1 为起点向后数,数到0 时比较当前1的个数和最大1 的个数,然后将遍历的起点放到当前0 的后面。 3、代码
leetcode 485. Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. ......
[leetcode]485. Max Consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: 分析: 给定一个由0和1组成的数组,要求返回最长连续1的个数。从头遍历数组,定义一个临时变量tmp记录当前连续1的个数,res记录最长连续1的个数,若tmp > res,则用tmp替换res...
Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3. ...
else if(nums[i]!=1) { if(max<ans) max = ans; ans = 0; } } return max>ans ? max : ans; } }; 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 参考 1. Leetcode_485. Max Consecutive Ones; ...
Leetcode之Max Consecutive Ones 问题 地址:https://leetcode.com/problems/max-consecutive-ones/description/)思路分析:这道题很简单吧,也没啥技巧,唯一可以注意的就是代码简洁的部分了,题目说的很清楚了,数组中只有0和1,遇到1的时候就累加,更新一下最大值,遇到0的时候计数器就重置为0 代码: ...