Github 同步地址: https://github.com/grandyang/leetcode/issues/829 参考资料: https://leetcode.com/problems/consecutive-numbers-sum/ https://leetcode.com/problems/consecutive-numbers-sum/discuss/129227/JAVA-easy-4-lines-O(n0.5) https://leetcode.com/problems/consecutive-numbers-sum/discuss/128959/...
Because we must find consecutive numbers that sum up to N, so for a given length K, we can only have at most 1 valid sequence. Based on this, we can solve this problem by looping through all possible length and check if a given length can provide a valid sequence. This will not cau...
classSolution:defconsecutiveNumbersSum(self,n:int)->int:result,i=0,1whilen>0:result+=not(n%i)n-=i i+=1returnresult
Explanation: 9 = 9 = 4 + 5 = 2 + 3 + 4 1. 2. 3. Example 3: Input: 15 Output: 4 Explanation: 15 = 15 = 8 + 7 = 4 + 5 + 6 = 1 + 2 + 3 + 4 + 5 1. 2. 3. 分析:https://leetcode.com/problems/consecutive-numbers-sum/discuss/209317/topic 这道题的要求的另一种...
【Leetcode】829. Consecutive Numbers Sum 云端漫步_b5aa关注IP属地: 华盛顿州 2019.04.19 04:55:46字数30阅读98 1 等差数列解,公差(common difference)为1 A valid sum cannot have more than d ~= sqrt(N) elements, so this is in O(sqrt(N))...
【Leetcode】Consecutive Numbers leetcode多表SQL文章分类代码人生 题目链接:https://leetcode.com/problems/consecutive-numbers/ 题目: Write a SQL query to find all numbers that appear at least three times consecutively. +—-+—–+ | Id | Num |...
Consecutive Numbers(找出连续出现的数字) 2、题目地址 https://leetcode.com/problems/consecutive-numbers/ 3、题目内容 写一个SQL,查出表Logs中连续出现至少3次的数字: +---+---+ | Id | Num | +---+---+ | 1 | 1 | | 2 | 1 | | 3 | ...
Write a SQL query to find all numbers that appear at least three times consecutively. +---+---+ | Id | Num | +---+---+ | 1 | 1 | | 2 | 1 | | 3 | 1 | | 4 | 2 | | 5 | 1 | | 6 | 2 | | 7 | 2 | +---+-...
LeetCode problem solving notes. Use the sliding window to solve the problem: input a positive integer `target`, and output all consecutive positive integer sequences (containing at least two numbers) whose sum is `target`.
log https://leetcode.com/problems/consecutive-numbers/ 方法一:做两个链接; 方法二:使用自带函数; SELECT DISTINCT L1.Num AS ConsecutiveNums FROM Logs L1, Logs L2, Logs L3 WHERE L1.Num = L2.Num AND L1.Num = L3.Num AND L1.Id = L2.Id + 1 AND L1.Id = L3.Id + 2本文...