Given an integern, returnthe number of ways you can writenas the sum of consecutive positive integers. Example 1: Input:n = 5Output:2Explanation:5 = 2 + 3 Example 2: Input:n = 9Output:3Explanation:9 = 4 + 5 = 2 + 3 + 4 Example 3: Input:n = 15Output:4Explanation:15 = 8 ...
Can you solve this real interview question? Consecutive Numbers Sum - Given an integer n, return the number of ways you can write n as the sum of consecutive positive integers. Example 1: Input: n = 5 Output: 2 Explanation: 5 = 2 + 3 Example 2:
1classSolution {2publicintconsecutiveNumbersSum(intN) {3intres = 1;4for(intk = 2; k < Math.sqrt(2 * N); k++) {5if((N - k * (k - 1) / 2) % k == 0) {6res++;7}8}9returnres;10}11}
Solution 1 of runtime O(sqrt(N)) that you came up. Because we must find consecutive numbers that sum up to N, so for a given length K, we can only have at most 1 valid sequence. Based on this, we can solve this problem by looping through all possible length and check if a give...
/* * @lc app=leetcode id=829 lang=cpp * * [829] Consecutive Numbers Sum */ // @lc code=start class Solution { public: int consecutiveNumbersSum(int N) { int res = 0; for (int m = 1; ; ++m) { int x = N - m * (m - 1) / 2; if (x <= 0) break; if (x % ...
Hence the overall complexity of the algorithm is O(sqrt(N)). Reference: https://leetcode.com/problems/consecutive-numbers-sum/discuss/129015/5-lines-C%2B%2B-solution-with-detailed-mathematical-explanation. 永远渴望,大智若愚(stay hungry, stay foolish)...
分析:https://leetcode.com/problems/consecutive-numbers-sum/discuss/209317/topic 这道题的要求的另一种说法: 把N表示成一个等差数列(公差为1)的和 我们不妨设这个数列的首项是x,项数为m,则这个数列的和就是[x + (x + (m-1))]m / 2 = mx + m(m-1)/2 = N ...
Consecutive Numbers(找出连续出现的数字) 2、题目地址 https://leetcode.com/problems/consecutive-numbers/ 3、题目内容 写一个SQL,查出表Logs中连续出现至少3次的数字: +---+---+ | Id | Num | +---+---+ | 1 | 1 | | 2 | 1 | | 3 | ...
Write a SQL query to find all numbers that appear at least three times consecutively. +---+---+ | Id | Num | +---+---+ | 1 | 1 | | 2 | 1 | | 3 | 1 | | 4 | 2 | | 5 | 1 | | 6 | 2 | | 7 | 2 | +---+-...
leetcode 129 Sum Root to Leaf Numbers 详细解答 解法1 迭代: 最开始的想法是将遍历的每一条路径都放到数组里,然后在求和。但这里其实不用,直接乘以10即可 解法2 递归:...628. Maximum Product of Three Numbers 最后答案 class Solution { public int maximumProduct(int[] nums) { int n=nums.length-...