So, please, what's the trick to simply include a local JAR, right in the project itself, in the output "fat JAR" using Maven?. Spent hours researching this basic configuration issue .
<build><plugins><plugin><groupId>org.apache.maven.plugins</groupId><artifactId>maven-shade-plugin</artifactId><executions><execution><id>make-assembly</id><phase>package</phase><goals><goal>shade</goal></goals><configuration><descriptorRefs><descriptorRef>jar-with-dependencies</descriptorRef></d...
点开lib里面我们运行程序的jar包,在打开manifest.MF文件,可以看到文件里面已经将所有依赖的jar的路径写入了classpath路径
一、首先是需要下载maven 二、在配置Maven环境时，通常需要设置M2_HOME和PATH环境变量。解压Maven压缩包到...
Maven用仓库外的jar进行编译 之所以采用Maven调用ant 进行编译,是因为有一些lib 并不在远程仓库里,而是直接放到project/lib目录下。 编译的时候要依赖这些lib包, maven里好像没什么办法把这些非仓库里的lib包加入到classpath中来,才采用调用ant的方式。 ps: 但是如果要采用这种把非仓库lib的加入到classpath的方式,就...
<include>**/*.xml</include> <include>**/*.properties</include> </includes> </resource> </resources> </build> </project> 定义打包方式 <packaging>war</packaging> 定义源文件编码 <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> ...
.build.directory}/it</cloneProjectsTo> <pomIncludes> <pomInclude>*/pom.xml</pomInclude> </pomIncludes> setup <postBuildHookScript>verify</postBuildHookScript> <localRepositoryPath>${project.build.directory}/local-repo</localRepositoryPath> <settingsFile>src/it/settings.xml</settingsFile> <goals...
-- 启动jar文件打包 --><fileSet><directory>${project.build.directory}</directory>./<includes><include>*.jar</include></includes></fileSet></fileSets></assembly> 在package.xml 中,我们还可以定义需要打包的依赖库、启动脚本文件、静态资源文件以及启动 jar 文件等内容。也可以在通过来排除一些我们不...
按快捷键shift+ctrl+alt+s或者通过左上角File菜单,进入Project Structure界面 2.进入打包界面,更改名字和文件位置 下面是瘦包的设置图 下面是胖包的设置过程 3.build 执行过后可以看到两种包出现在左侧out文件夹下 法二,maven插件帮助打胖瘦jar包 在maven工程的pom文件的插件部分加入以下代码(注意:插入在build下,而...
So I can't just create a common1.war and then include that in AppA/WEB-INF/lib... Tim Holloway Saloon Keeper Posts: 28293 204 I like... posted 16 years ago No, but you can create a common1.jar and include it. Of course, that supposes you're talking classes, property files ...