The code implementing thewhileloop is in theex_while_loop_ML_stepfunction inex_while_loop_ML.c: /* Model step function */ void ex_while_loop_ML_step(void) { int32_T num_iter; boolean_T flag; boolean_T func_flag_0; /* MATLAB Function: '<Root>/MATLAB Function' */ func_flag_0 ...
【题目】matlab while循环求解答Using a while loop, starting at n = 1 calculate all the values of n ≥ 1 such thatthe differenceAn =1 /n -1/(n+1)is greater than 0.000001 (which can also be written inMatlab as 1e-6).Start a counter, n = 1 and create a variablediff with initial...
This MATLAB function evaluates an expression, and repeats the execution of a group of statements in a loop while the expression is true.
答案 a=randi([-10 10],1,20);b=a<0;k=1;while any(b)num=sum(b);a(b)=randi([-10 10],1,num);k=k+1;b=a<0;enddisp(['重复' num2str(k) '次后,数列为:']);disp(a);相关推荐 1matlab中while loop 的问题lz是大一新生,今天作业,英文的,翻译的不好不要见怪。。。苦思冥想不知道怎...
I want an overall while loop that is executed until a certain condition is true (let's say J=13). The whole loop starts with J=5 and j=1 and inside the while loop j is raised +1 until j =J. Then the second while loop starts with J = J+1. How can I shorten this code ...
The MATLABwhileloop is similar to ado...whileloop in other programming languages, such as C and C++. However,whileevaluates the conditional expression at the beginning of the loop rather than the end. do % Not valid MATLAB syntaxstatementswhileexpression ...
This MATLAB function evaluates an expression, and repeats the execution of a group of statements in a loop while the expression is true.
Exit Loop Before Expression Is False Sum a sequence of random numbers until the next random number is greater than an upper limit. Then, exit the loop using abreakstatement. limit = 0.8; s = 0;while1 tmp = rand;iftmp > limitbreakends = s + tmp;end ...
%%MAIN LOOP whilex_2_new(i)>=x_2_new(i-1) K=K+1; i=i+1; beta=0; %%SECOND LOOP whilebeta<0.1 P_1=P_1+0.1; P_2=P-P_1; x_1=K*log(1+P_1/(2+1/P_1)); x_2=log(1+P_2); beta=x_1/x_2; end x_2_new(i)=x_2; ...
改成while循环的代码：s=0;x=input('Enter x');n=0;while n<=1000 s=s+((-1)^n*x^(2*n+1))/(2*n+1); n=n+1;endtheta=pi/2-s s=0