1.3000 (5)Create a matrix A and compute the smallest elements in each column as well as the row indices of A in which they appear. A= [19-2;84-5] A = 1 9 -2 8 4 -5 [M,I] = min(A) M = 1 4 -5 I = 1 2 2 (6)Create a matrix and return the smallest value between...
... = min(DMObj1, [],Dim)specifies which dimension to return the minimum values for, that is each column or each row in a DataMatrix object. IfDim=1, returnsM, a row vector containing the minimum value in each column. IfDim=2, returnsM, a column vector containing the minimum value...
); % If just 'defaults' passed in, return the default options in X if nargin==1 && nargout <= 1 && strcmpi(FUN,'defaults') X = defaultopt; return end if nargin < 10 options = []; if nargin < 9 NONLCON = []; if nargin < 8 UB = []; if nargin < 7 LB = []; if narg...
Hello, I have a cell array by name m1 of size 374 * 3 (where m1(1,1}=1 * 8,m1{1,2}=1*8 and m1{1,3}=1*1..totally there are 17 cells)..Now i want minimum value index from all this cells... for example if m1{1,1}=[0.34463 0.3276 0.3615 0.3446 0.3559 0.3389 0....
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Create a matrix A and return the minimum value of each row in the matrix M. Use the "linear" option to also return the linear indices I such that M = A(I). Get A = [1 2 3; 4 5 6] A = 2×3 1 2 3 4 5 6 Get [M,I] = min(A,[],2,"linear") M = 2×1 ...
You requested a minimum of 7 workers, but the cluster "local" has the NumWorkers property set to allow a maximum of 4 workers. To run a communicating job on more workers than this (up to a maximum of 512 for the Local cluster), increase the value of the NumWorkers property for the ...
Create a matrix A and return the minimum value of each row in the matrix M. Use the "linear" option to also return the linear indices I such that M = A(I). Get A = [1 2 3; 4 5 6] A = 2×3 1 2 3 4 5 6 Get [M,I] = min(A,[],2,"linear") M = 2×1 ...
of the efficient frontier warning off; NumAssets=size(Covariance,2); %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % determine return of minimum-risk portfolio First...
Peak NumberLeft Interval Lies Between Peak andRight Interval Lies Between Peak andLowest Point on the Left IntervalLowest Point on the Right IntervalReference Level (Highest Minimum) 1Left endCrossing due to peak2Left endpointaa 2Left endRight endLeft endpointhLeft endpoint ...