i have to find the index of the same value in an array,see the following example a=[1 2 3 1] i want b=[1 4] as output..how can i do this? A solution using find is this u=unique(a) n=histc(a,u) find(a==u(n>1)) but if in the a array there isn't 2 or more sam...
Additionally, I have an array called 'lonlat' that contains longitudes in the first column and latitudes in the second column. For every latitude and longitude pair in 'lonlat' I need to find the index of the closest latitude and longitude pair in 'loc'...
can anybody help to find index from the cell array (attached) and then extract desired value from it. For example, I am looking for values (temp_glb) in between lon_glb[28 45], and lat_glb[40 49]. Thanks 댓글 수: 0
fprintf('value of a: %d \n', a); end 1. 2. 3. 输出结果为: value of a: 10 value of a: 11 value of a: 12 value of a: 13 value of a: 14 value of a: 15 value of a: 16 value of a: 17 value of a: 18 value of a: 19 value of a: 20 1. 2. 3. 4. 5. 6. ...
k = find(X) k = find(X,n) k = find(X,n,direction) [row,col] = find(___) [row,col,v] = find(___)Description k = find(X) returns a vector containing the linear indices of each nonzero element in array X. If X is a vector, then find returns a vector with the same or...
Find the nonzero elements in a 4-by-2-by-3 array. Specify two outputs, row and col, to return the row and column subscripts of the nonzero elements. When the input is a multidimensional array (N > 2), find returns col as a linear index over the N-1 trailing dimensions of X. Ge...
Hello, I have a cell array by name m1 of size 374 * 3 (where m1(1,1}=1 * 8,m1{1,2}=1*8 and m1{1,3}=1*1..totally there are 17 cells)..Now i want minimum value index from all this cells... for example if m1{1,1}=[0.34463 0.3276 0.3615 0.3446 0.3559 0.3389 0....
% options structure in PROBLEM.options, and solver name 'fmincon' in % PROBLEM.solver. Use this syntax to solve at the command line a problem % exported from OPTIMTOOL. The structure PROBLEM must have all the fields. % % [X,FVAL] = FMINCON(FUN,X0,...) returns the value of the obje...
for index=1:2 if index==1 dosomething(index); ... end % End if end % End for 条件式 避免复杂的条件表达式,改用临时逻辑变量。 isValid = (v >= lowerLimit) & (v <= upperLimit); isNew = ismember(v, valueArray); 避免使用条件表达式if 0。
second. Find the first column to start as a cost index. Cost_Column plays a very important role in defining the size of the column in the for loop. Automatic operation can be correctly realized no matter how the number of matrix columns changes. Next, measure the size of the original ...