function split(str, delimiter) local result = {} -- 存储分割结果的表 local from = 1 local delim_len = string.len(delimiter) local pos -- 循环查找分隔符并分割字符串 while true do pos = string.find(str, delimiter, from) if not po
function split(str,delimiter) local dLen = string.len(delimiter) local newDeli = '' for i=1,dLen,1 do newDeli = newDeli .. "["..string.sub(delimiter,i,i).."]" end local locaStart,locaEnd = string.find(str,newDeli) local arr = {} local n = 1 while locaStart ~= nil do ...
### 1. 实现 `string.split()` 函数 首先,我们需要定义一个函数来根据指定的分隔符将字符串分割成多个子字符串。下面是一个简单的实现: ```lua -- 定义 string.split 方法 function string:split(delimiter) local result = { self } -- 初始化结果表,包含原始字符串 local pattern = string.format("(...
AI代码解释 functionstring:split_lite(sep)local splits={}ifsep==nil then--returntablewithwhole str table.insert(splits,self)elseif sep==""then--returntablewitheach single character local len=#selffori=1,lendotable.insert(splits,self:sub(i,i))endelse--normal split use gmatch local pattern...
方法二 可以改为string.split: functionsplit(str, delimiter)localresult ={}localstart =1localfound =string.find(str, delimiter)whilefound ~=nildotable.insert(result,string.sub(str, start, found -1)) start= found + #delimiter found=string.find(str, delimiter, start)endtable.insert(result,string...
方法二 可以改为string.split: functionsplit(str, delimiter)localresult ={}localstart =1localfound =string.find(str, delimiter)whilefound ~=nildotable.insert(result,string.sub(str, start, found -1)) start= found + #delimiter found=string.find(str, delimiter, start)endtable.insert(result,string...
个特定的分隔符,一般我喜欢用 '|' function getcountinstr(str,del) local count = 0 local pos = 1 while true do pos = str:find(del, pos+1) if not pos then break end count = count + 1 end return count end --分割到table中 function split(str,reps) local resultStrList = {} string...
lua语言定义split函数 lua string.pack,Lua中字符串管理是核心内容之一(另一个当然就是表的管理)。Lua脚本中用到的字符串,解析时用到的符号,及一些运行时相关的字符串都保存在全局字符串表中,全局字符串表就是tree.c中的string_root数组。同样的字符串在Lua的全局字符
代码如下：function string.split(input, delimiter)input = tostring(input)delimiter = tostring(delimiter)if (delimiter=='') then return false end local pos,arr = 0, {} -- for each divider found for st,sp in function() return string.find(input, delimiter, pos, true) end do ta...
1. 利用string库的gsub函数 functionsplit( str,reps )localresultStrList ={}string.gsub(str,'[^'..reps..']+',function( w )table.insert(resultStrList,w)end)returnresultStrListend string库的gsub函数,共三个参数: str是待分割的字符串