第三步:在电流源上单击鼠标右键。显示 Current Source - I1,选择 Advanced,如下图 (图9) 所示: 图9 设定电流源1 弹出Independent Current Source - I1 窗口后,选择 PULSE,在 I1[A]-Ton[s] 填框中输入下图 (图10) 所示的数据: 图10 设定电流源2 第四步:最后更改模拟的运行时间。上述设...
Independent voltage source ?Independent current source ?JFET transistor ?Mutual inductance ?Independent voltage source ?Current controlled switch ?Subcircuit ?MOSFET transistor ?MESFET transistor ?many more 2011 Linear Technology 20 Drawing Lines and Labeling NodesDrawing Lines and Labeling Nodes Draw Wire ...
Insert a .step command into your schematic as a SPICE directive and step the independent current source from a light load to maximum current load and define the step increments. (You can use the S hotkey to add and place a SPICE directive.) Here, we step the independent current source...
Independent current source ? Current controlled switch ? JFET transistor ? Subcircuit ? Mutual inductance ? MOSFET transistor ? MESFET transistor ? …many more ? 2011 Linear Technology 20 Drawing Lines and Labeling Nodes Draw Wire Do not forget to place a Place Ground Label Node ground in your ...
In LTspice, AC analysis involves computing the AC complex node voltages as a function of frequency using an independent voltage or current source as the driving signal. The small signal analysis results are plotted in the waveform viewer as magnitude and phase over frequency. ...
我们的RC电路是想在时间域对电压响应OK完后,把长方行.tran 2ms贴到线路图的电压源下.现在我们设计电压源的参数.理想下电压从零到 1V用.右键点电压源选好 ADVANCEDIndependent Voltage Source - VFunctions 厂(nonejC PULSEM V2 Tdelay Trise TfdITon Period Ncycle)广 SI NE/offset Vamp Freq Td Theta Phi...
LTspice电路仿真使用说明书与功能介绍
• LT6108: High side current sense amplifier with reference and comparator www.linear.com/6108 • LTC6360: Very low noise single- ended SAR ADC driver with true zero output www.linear.com/6360 V IN 1.8V TO 5.5V OUT IN ≥ 3V Download the LTspice IV demonstration circuit for this 1...
关于电路模拟器LTspice 中的疑问 小弟是LTSPICE的菜鸟,对使用dependentsourse很迷惑,1.我创建一个电路,由一个independent的电压源v1一个dependent电压源e1和一个电阻R串联,最后接个地,我在e1的value里面填上valu... 小弟是LTSPICE的菜鸟,对使用dependent sourse 很迷
看样子你要仿一个二极管。首先 value=｛2*v(v1)｝；其次，LT貌似不做输入参数的迭代，所以会有这样的错误提示（如果能就直接能仿TCM了）最后N-R解吉尔霍夫的时候，只计算节点电压，所以两点电压差用｛v(label1)-v(label2)｝