publicclassSolution { publicString longestCommonPrefix(String[] strs) { if(strs ==null|| strs.length ==0) { return""; } String prefix = strs[0]; for(inti =1; i < strs.length; i++) { intj =0; while( j < strs[i].length() && j < prefix.length() && strs[i].charAt(...
package LeetCode_1392 /** * 1392. Longest Happy Prefix * https://leetcode.com/problems/longest-happy-prefix/ * * A string is called a happy prefix if
LeetCode: Longest Common Prefix Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string “”. Example 1: Example 2: Note: All given inputs...Longest Common Prefix #14 Longest Common Prefix 最大公共...
LeetCode每日一题:14.longest-common-prefix(最长公共前缀),首先注意下前缀/后缀和子串的区别:"前缀"和"后缀":"前缀"指除了最后一个字符以外,一个字符串的全部头部组合;"后缀"指除了第一个字符以外,一个字符串的全部尾部组合。"子串":可以出现在一个字符串的任意位
package leetcode import ( "sort" ) func longestWord(words []string) string { sort.Strings(words) mp := make(map[string]bool) var res string for _, word := range words { size := len(word) if size == 1 || mp[word[:size-1]] { if size > len(res) { res = word } mp[wor...
解法就是扫一次。不过各种边界条件很容易出错。 View Code SOULTION2: 感谢大神的灵感http://blog.csdn.net/fightforyourdream/article/details/14642079 重新改写: View Code 请Floow主页君的GitHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/LongestCommonPrefix.java...
} Write a function to find the longest common prefix string amongst an array of strings. 题意有些模糊,是说这些strs都有common prefix. 题解抄自ref link里 “ 题解: 解题思路是,先对整个String数组预处理一下,求一个最小长度(最长前缀肯定不能大于最小长度)。
14. Longest Common Prefix Write a function to find the longest common prefix string amongst an array of strings. 1/**2* @param {string[]} strs3* @return {string}4*/5varlongestCommonPrefix =function(strs) {67//每次都拿一个最长公共前序列去比较得了 比如string[] = ["aa","ab","ap"...
Got from: https://discuss.leetcode.com/topic/21068/my-7-lines-recursive-java-solution/4 classSolution {/*** The goal is to complete s into a Palindrome. We could tackle this problem little by little. * <p> * We need to split the string into two parts, s[0,j), s[j,len), suc...
=== 第二次过这道题,自己写出来了代码,调了两次AC了。 classSolution {public:stringlongestCommonPrefix(vector<string>&strs) {if( strs.size()==0)return"";if( strs.size()==1)returnstrs[0];stringcommon_pre = strs[0];for(inti=1; i<strs.size(); ++i ) {if( common_pre.size()...