class Solution { public String longestCommonPrefix(String[] strs) { if (strs.length == 0) return ""; String prefix = strs[0]; for (int i = 1; i < strs.length; i++) while (strs[i].indexOf(prefix) != 0) { prefix = prefix.substring(0, prefix.length() - 1); if (pref...
Problem:Write a function to find the longest common prefix string amongst an array of strings. Solution:题意要求求取字符串数组的最长公共前缀子串。从位置0开始,对每一个位置比较所有的字符串,直到遇到不匹配的字符串位置 classSolution {public:stringlongestCommonPrefix(vector<string>&strs) {if(strs.emp...
import pandas as pd class Solution(object): def longestCommonPrefix(self, strs): for i in strs: if len(i) > 200 or len(i) < 1: # 控制列表strs长度 return False if not i.islower(): # 限制strs每一个元素必须为小写 return False strs_dict = {} #为strs的每一个元素创建一个空字...
java代码: class Solution {publicStringlongestCommonPrefix(String[] strs) { String res = strs.length ==0?"":strs[0];for(inti=1; i<strs.length; i++){ res = calcPre(res, strs[i]); }returnres; }publicStringcalcPre(String nowPre, String nowStr){ StringBuffer sb =newStringBuffer(...
class Solution { public: string longestCommonPrefix(vector<string> &strs) { if(strs.size()==0){ return ""; } sort(strs.begin(),strs.end()); int len=strs.size(); int l=min(strs[0].size(),strs[len-1].size()); for(int i=0;i<l;i++){ if(strs[0][i]!=strs[len...
另外,务必增加一个边界条件: Input: [],Output: '',也就意味着首先要判断Input是否为空; 整体的代码如下: classSolution:deflongestCommonPrefix(self,strs:List[str])->str:preStr=''ifnotlen(strs):# empty strsreturnpreStrshortLength=min([len(s)forsinstrs])foriinrange(1,shortLength+1):eleLis...
leetcode 14. Longest Common Prefix 给n个字符串,求最长公公前缀。直接逐位扫判断就行。 class Solution(object): def longestCommonPrefix(self, strs): """ :type strs: List[str] :rtype: str """ lenS = len(strs) if lenS == 0: return ''...
class Solution { public: string longestCommonPrefix(vector<string> &strs) { if (strs.empty()) { return ""; } string common = strs[0]; vector<string>::size_type size = strs.size(); int length;//保存要比较的两个字符串的最小长度,只在最小长度范围内进行比较 ...
编写一个函数来查找字符串数组中的最长公共前缀。 如果不存在公共前缀,返回空字符串 ""。 示例 1: 输入:strs = ["flower","flow","flight"] 输出:"fl" 示例 2: 输入:strs = ["dog","racecar","car"] 输出:"" 解释:输入不存在公共前缀。  
class Solution { public: string longestCommonPrefix(vector<string>& strs) { string result; if (strs.size() == ) { return result; } int minLength = 0x7FFFFFFF; for (int i = ; i < strs.size(); ++i) { int si = strs[i].size(); ...