Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string"". Note: All given inputs are in lowercase letters a-z. 中文题目: 编写一个函数来查找字符串数组中的最长公共前缀。 如果不存在公共前缀,返回空字符串 "...
Question: Write a function to find the longest common prefix string amongst an array of strings. If there is no common prefix, return an empty string "". Note: All given inputs are in lowercase letters a-z. 中文题目: 编写一个函数来查找字符串数组中的最长公共前缀。 如果不存在公共前缀,返回...
代码语言:javascript 复制 classSolution(object):deflongestCommonPrefix(self,strs):""":type strs:List[str]:rtype:str"""ifnot strs:return""foriinrange(len(strs[0])):forstringinstrs[1:]:# flow,flightifi>=len(string)or string[i]!=strs[0][i]:returnstrs[0][:i]returnstrs[0]...
代码语言:javascript 复制 classSolution{publicStringlongestCommonPrefix(String[]strs){if(strs==null||strs.length==0)return"";String prefix=strs[0];for(int i=1;i<strs.length;i++){while(strs[i].indexOf(prefix)!=0){prefix=prefix.substring(0,prefix.length()-1);if(prefix.isEmpty())r...
Write a function to find the longest common prefix string amongst an array of strings. 解题思路: class Solution: # @return a string def longestCommonPrefix(self, strs): if strs == []: return '' minl = 99999 for i in strs: if len(i) < minl: minl = len(i) pre = '' for...
取得第一个做样板,然后与第二个字符串比较,看它们是否有共同前缀,没有那么将前缀的缩短一点,从后面砍掉一个字符再比较,有了前缀就再与第三,第四个比较 javascript function longestCommonPrefix(strs) { if (strs.length == 0) return
If there is no common prefix, return an empty string"". Solution of Longest Common Prefix Input Example: Example 1:Let the set of strings to be {"flower", "fly", "flow"} The longest common prefix is "fl"Example 2:Let the set of strings to be {"dog", "donkey", "door", "cat...
14. Longest Common Prefix 最长公共前缀子串 14. Longest Common Prefix DescriptionHintsSubmissionsDiscussSolution DiscussPick One Write a function to find the longest common prefix string amongst an array of strings. ... 【leetcode】最长公共前缀 Longest Common Prefix【python】 ...
impl Solution { pub fn longest_common_prefix(strs: Vec<String>) -> String { if strs.len() == 0 { return "".to_string(); } if strs.len() == 1 { return strs[0].clone(); } if strs[0].len() == 0 { return "".to_string(); } let mut common = String::new(); le...
for i,c in enumerate(x): for y in strs[1:]: if len(y) <= i or c != y[i]: return x[:i] return x 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 方法二:zip class Solution: def longestCommonPrefix(self, strs: List[str]) -> str: ...