class Solution { public String longestCommonPrefix(String[] strs) { //判断边界条件 if(strs==null||strs.length==0)return ""; String res=strs[0];//取第一个 for(int i=1;i<strs.length;i++){ while(strs[i].indexOf(res)!=0){ res=res.substring(0,res.length()-1); } } retu...
2、minLen的初值一开始写成了MIN_VALUE. 参考答案Code: 1publicString longestCommonPrefix(String[] strs) {2if(strs ==null|| strs.length == 0)3return"";4String pre = strs[0];5for(inti = 1; i < strs.length; i++)6while(strs[i].indexOf(pre) != 0)7pre = pre.substring(0, p...
import java.util.Iterator; //题目链接:https://leetcode.cn/problems/longest-common-prefix/ public class T14 { public static void main(String[] args) { // 测试一把 Solution solution = new Solution(); String[] str = { "flower","flow","flowight"}; String string = solution.longestCommon...
publicclassLongestCommonPrefix{publicStringlongestCommonPrefix(String[]strs){if(strs==null||strs.length==0){return"";}// 将第一个字符串作为初始前缀Stringprefix=strs[0];// 从第二个字符串开始与前缀进行比较for(inti=1;i<strs.length;i++){// 不断缩减前缀长度,直到找到公共前缀while(strs[i...
最长公共前缀 LCP(longest common prefix) Leetcode: 编写一个函数来查找字符串数组中的最长公共前缀。如果不存在公共前缀,返回空字符串 ""。 思路:先将字符串数组排序,在比较第一个字符串与最后一个字符串的公共前缀即可 eg:["abcddd","abbddd","abccc"] -> ["abbddd","abccc","abcddd"], ...
https://leetcode-cn.com/problems/longest-common-prefix/ 编写一个函数来查找字符串数组中的最长公共前缀。 如果不存在公共前缀,返回空字符串 ""。 示例1: 输入: ["flower","flow","flight"] 输出: "fl" 示例2: 输入: ["dog","racecar","car"] ...
class Solution {public String longestCommonPrefix(String[] strs) {if(strs.length == 0){return "";}String ans=strs[0];for(int i=1;i<strs.length;i++){int j=0;for(;j<ans.length() && j<strs[i].length();j++){if(ans.charAt(j) != strs[i].charAt(j))break;}ans = ans...
public class Solution { public String longestCommonPrefix(String[] strs) { if (strs == null || strs.length == 0) { return ""; } // 假设第一个字符串是最长公共前缀的初始值 String prefix = strs[0]; // 遍历字符串数组 for (int i = 1; i < strs.length; i++) { // 如果当...
public String longestCommonPrefix(String[] strs) { for(int i = 0; i < strs.length; i++) { if(strs[i].equals("")) { return ""; } } DictionaryTree dictionaryTree = new DictionaryTree(); for(int i = 0; i < strs.length; i++) { ...
classSolution{publicStringlongestCommonPrefix(String[]strs){if(strs.length==0||strs==null)return"";Stringans=strs[0];for(inti=1;i<strs.length;i++){intj=0;for(;j<ans.length()&&j<strs[i].length();j++){if(ans.charAt(j)!=strs[i].charAt(j))break;}ans=ans.substring(0,j);...