TreeNode*root =newTreeNode(arr[(start + end)/2]); root-> left = sortedArrayTree(arr, start, (start + end)/2-1); root-> right = sortedArrayTree(arr, (start + end)/2+1, end);returnroot; }//给定有序链表,构造高度平衡二叉树Tree
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: Given th...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) { val = x; next = null; }7* }8*/9/**10* Definition for binary tree11* public class TreeNode {12* int val;13* TreeNode left;14* TreeNode right;15* TreeNode...
TreeNode *solve(ListNode *head,int left,int right) { if(left > right) return NULL; int mid = (left+right)/2; TreeNode *leftNode=solve(head, left, mid-1); for(int i=left;i<mid;i++) head=head->next; TreeNode *rightNode=solve(head->next, mid+1,right); TreeNode *root=new ...
array = list.toArray();//then use array to construct the BST;BST tree = new BST (array); ...
click to show hints. Anwser 1 : 代码语言:javascript 代码运行次数:0 运行 AI代码解释 /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
Can you solve this real interview question? Flatten Binary Tree to Linked List - Given the root of a binary tree, flatten the tree into a "linked list": * The "linked list" should use the same TreeNode class where the right child pointer points to the
也就是6作为5的右孩子,5作为4的右孩子,以此类推。 class Solution { private TreeNode prev = null; public void flatten(TreeNode root) { if (root == null) return; flatten(root.right); flatten(root.left); root.right = prev; root.left = null; prev = root; } }...
msdn叙述: The SortedDictionary<TKey, TValue> generic class is a binary search tree with O(log n) retrieval, where n is the number of elements in the dictionary. In this, it is similar to the SortedList<TKey, TValue> generic class. The two classes have similar object models, and both...
伪代码 代码 funcsortedListToBST(head*ListNode)*TreeNode{nums:=make([]int,0)forhead!=nil{nums=append(nums,head.Val)head=head.Next}returntobst(nums)}functobst(nums[]int)*TreeNode{iflen(nums)==0{returnnil}k:=len(nums)/2node:=&TreeNode{Val:nums[k]}node.Left=tobst(nums[:k])node....