TreeNode*root =newTreeNode(arr[(start + end)/2]); root-> left = sortedArrayTree(arr, start, (start + end)/2-1); root-> right = sortedArrayTree(arr, (start + end)/2+1, end);returnroot; }//给定有序链表,构造高度平衡二叉树TreeNode *sortedListToBST(ListNode *head) {if(!head)...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) { val = x; next = null; }7* }8*/9/**10* Definition for binary tree11* public class TreeNode {12* int val;13* TreeNode left;14* TreeNode right;15* TreeNode...
public TreeNode sortedListToBST(ListNode head) { ArrayList<Integer> nums = new ArrayList<>(); while (head != null) { nums.add(head.val); head = head.next; } return sortedArrayToBST(nums); } public TreeNode sortedArrayToBST(ArrayList<Integer> nums) { return sortedArrayToBST(nums, 0...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: Given th...
Can you solve this real interview question? Convert Sorted List to Binary Search Tree - Given the head of a singly linked list where elements are sorted in ascending order, convert it to a height-balanced binary search tree. Example 1: [https://asse
https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ 题目: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 思路: 简单起见,先把链表值存到数组中,用数组递归感觉会简单点。。
array = list.toArray();//then use array to construct the BST;BST tree = new BST (array); ...
click to show hints. Anwser 1 : 代码语言:javascript 代码运行次数:0 运行 AI代码解释 /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
C++ program to convert a given binary tree to doubly linked list #include<bits/stdc++.h>usingnamespacestd;structnode{intdata;node*left;node*right;};//Create a new nodestructnode*create_node(intx){structnode*temp=newnode;temp->data=x;temp->left=NULL;temp->right=NULL;returntemp;}//c...
伪代码 代码 funcsortedListToBST(head*ListNode)*TreeNode{nums:=make([]int,0)forhead!=nil{nums=append(nums,head.Val)head=head.Next}returntobst(nums)}functobst(nums[]int)*TreeNode{iflen(nums)==0{returnnil}k:=len(nums)/2node:=&TreeNode{Val:nums[k]}node.Left=tobst(nums[:k])node....