*/classSolution{public List<Integer>inorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){// left firstif(current.left==null){result.add(current.val);current=current.right;}// if there is left, get the rightmost ...
1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12vector<int> inorderTraversal(TreeNode *root) {13vector<int>ret;14if(root ==...
首先发明这个算法的人肯定是对那个什么Threaded Binary Tree烂熟于心啊;其次,对inorder遍历也是理解透彻啊。。。 再次,这人思维肯定特清晰。 Reference:http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion-and-without-stack/
node_e.assignchild(node_h, node_i); preorder_visit(node_a);//先序 Console.WriteLine(); inorder_visit(node_a);//中序 Console.WriteLine(); postorder_visit(node_a);//后序 Console.WriteLine(); node node_1 =newnode("1"); node node_2 =newnode("2"); node node_3 =newnode("3"...
Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
Binary Tree Preorder Traversal 题目链接 题目要求: Given a binary tree, return thepreordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,2,3]. Note: Recursive solution is trivial, could you do it iteratively?
publicList<Integer>inorderTraversal3(TreeNoderoot){List<Integer>ans=newArrayList<>();TreeNodecur=root;while(cur!=null){//情况 1if(cur.left==null){ans.add(cur.val);cur=cur.right;}else{//找左子树最右边的节点TreeNodepre=cur.left;while(pre.right!=null&&pre.right!=cur){pre=pre.right;}...
inorder 遍历 tree 基本没难度,然后还算是 Medium... 傻逼。。。 主要考的还是非递归遍历。 代码如下: ** 总结: inorder tree ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { *...
Binary search tree traversal in order, postorder, and preorder traversal. Top of the tree, the height of the tree inorder-traversalpreorder-traversalpostorder-traversaltop-view-binary-treeheight-of-tree UpdatedSep 2, 2020 Python jaydattpatel/Binary-Tree ...
Morris Traversal is a method based on the idea of a threaded binary tree and can be used to traverse a tree without using recursion or stack. Morris traversal involves: Step 1: Creating links to inorder successors Step 2: Printing the information using the created links (the tree is altered...