{"string1","string2"}, {"string3","string4"} } I started looking at ToDictionary, then moved over to selecting an anonymous type but I'm not sure how to say "return the next two strings as a pair". My code looks similar to this at the time of writing: publicvoidmyMethod(){va...
ADD Root Node to XML in C# add string data to IList collection Add strings to list and expiry each item in certain period of time add text file data into arraylist Add Text to a Textbox without removing previous text Add Two Large Numbers Using Strings - Without Use of BigInt Add user...
string[] sentences = text.Split(['.', '?', '!']); // Define the search terms. This list could also be dynamically populated at run time. string[] wordsToMatch = [ "Historically", "data", "integrated" ]; // Find sentences that contain all the terms in the wordsToMatch ar...
IEnumerable<string>justStrings=vals.OfType<string>(); 当在foreach语句中列举(enumerate)变量 justStrings 中的数据时,将得到两个依次为“Hello”和“World”的string字符串序列(a sequence of two strings )。 2.ToList,ToArray: 对应用程序想缓存查询赋值的结果,ToList 和 ToArray 这两个操作符提供用来强制...
没有任何错误检查，但它会给出结果：
Console.WriteLine("Press any key to exit.") Console.ReadKey() End Sub Shared Sub OutputQueryResults(ByVal query As IEnumerable(Of String), ByVal message As String) Console.WriteLine(System.Environment.NewLine & message) For Each item As String In query Console.Write...
Using LINQ to turn enumerables into delimited strings can cause serious performance problems Modern .NET (since .NET 4) This is for an array, list or any type that implements IEnumerable: string.Join(delimiter, enumerable); And this is for an enumerable of custom objects: string.Join(...
You can query a string as a sequence of characters in LINQ. This article contains several examples you can use or modify to suit your needs.
{nameMatch}":"""); static void OutputQueryResults(IEnumerable<string> query, string message) { Console.WriteLine(Environment.NewLine + message); foreach (string item in query) { Console.WriteLine(item); } Console.WriteLine($"{query.Count()} total names in list"); } /* Output: Simple ...
public string SchoolName { get; set; } } static void Main(string[] args) { IList<School> schools = new List<School>(); schools.Add(new School() { SchoolId = 1, SchoolName = "BeiJing Middle School " }); schools.Add(new School() { SchoolId = 2, SchoolName = "ShangHai Middle ...