Input:head = [1], pos = -1Output:no cycleExplanation:There is no cycle in the linked list. Constraints: The number of the nodes in the list is in the range[0, 104]. -105<= Node.val <= 105 posis-1or avalid indexin the linked-list. Follow up:Can you solve it usingO(1)(i.e. constant) memory?
142. Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull. To represent a cycle in the given linked list, we use an integerposwhich represents the position (0-indexed) in the linked list where tail connects to. Ifposis-1...
boolLeetCode::hasCycle(ListNode *head){if(!head)returnfalse; ListNode*p = head, *q =head;while(q){ p= p->next;//p每次前进一步if(!q->next)returnfalse;//q是否到链尾q = q->next->next;//q每次前进两步if(p == q)returntrue;//重合则有环}returnfalse; } 题目:Linked List CycleII...
来自专栏 · LeetCode Description Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If...
next = ListNode(list[i]) cur = cur.next return head ## 头元素指代一个链表 这里暂时还没想明白怎么初始化带有环的链表,所以这次就先直接在LeetCode中提交 solution。 class Solution: def hasCycle(self, head:ListNode) -> bool: seen = set() ## 空集合遍历收集元素 while head: ## 存在头结点 ...
leetcode -- Linked List Cycle -- 重点 一开始我错误的code: class Solution(object): def hasCycle(self, head): """ :type head: ListNode :rtype: bool """ if not head : return False slow, fast = head, head while fast and fast.next and fast != slow:#这里这个条件fast!=slow,使得在...
【Leetcode】Linked List Cycle II https://leetcode.com/problems/linked-list-cycle-ii/ 题目: null. Note: Follow up: Can you solve it without using extra space? 思路: 首先确定循环是否存在,若存在,根据 循环结点个数/结点相对移动次数 就会相遇的规律 得到循环结点个数,再从头开始遍历,相对移动速度为...
Problem link: https://leetcode.com/problems/linked-list-cycle-ii/有任何错误欢迎指出,有任何问题欢迎留言,谢谢观看, 视频播放量 94、弹幕量 1、点赞数 1、投硬币枚数 2、收藏人数 1、转发人数 1, 视频作者 dddeng12, 作者简介 ,相关视频:51. N 皇后 (N-queens),重
141 Linked..判断链表 LinkList 是否带循环。Given a linked list, determine if it has a cycle in it.To represent a cycle in t
Explanation: There is a cycle in the linked list, where tail connects to the second node. image.png 二、解决思路 方法一:使用HashMap存储遍历链表,并判重,O(n) 方法二:使用一快一慢指针检查是否相等,O(n) 三、算法实现 publicstatic booleanisCycle(Node head){if(head==null)returnfalse;boolean fla...