Input:head = [3,2,0,-4], pos = 1Output:tail connects to node index 1Explanation:There is a cycle in the linked list, where tail connects to the second node. Example 2: Input:head = [1,2], pos = 0Output:tail con
boolLeetCode::hasCycle(ListNode *head){if(!head)returnfalse; ListNode*p = head, *q =head;while(q){ p= p->next;//p每次前进一步if(!q->next)returnfalse;//q是否到链尾q = q->next->next;//q每次前进两步if(p == q)returntrue;//重合则有环}returnfalse; } 题目:Linked List CycleII...
next = ListNode(list[i]) cur = cur.next return head ## 头元素指代一个链表 这里暂时还没想明白怎么初始化带有环的链表,所以这次就先直接在LeetCode中提交 solution。 class Solution: def hasCycle(self, head:ListNode) -> bool: seen = set() ## 空集合遍历收集元素 while head: ## 存在头结点 ...
运行时间0ms,这里要注意刚开始的判断和while循环结束条件,因为hare跑的比tortoise快,所以对于循环结束的判断只要判断hare就行了。 2、Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull. Note: Do not modify the linked list. Follow up...
来自专栏 · LeetCode Description Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to. If...
【Leetcode】Linked List Cycle II https://leetcode.com/problems/linked-list-cycle-ii/ 题目: null. Note: Follow up: Can you solve it without using extra space? 思路: 首先确定循环是否存在,若存在,根据 循环结点个数/结点相对移动次数 就会相遇的规律 得到循环结点个数,再从头开始遍历,相对移动速度为...
Leetcode: Linked List Cycle 题目: Given a linked list, determine if it has a cycle in it. 思路分析: 利用快慢指针slow,fast。 slow指针每次走一步,fast指针每次走两步,倘若存在环,则slow和fast必定在某一时刻相遇。 C++参考代码: /** * Definition for singly-linked list....
141 Linked..判断链表 LinkList 是否带循环。Given a linked list, determine if it has a cycle in it.To represent a cycle in t
Problem link: https://leetcode.com/problems/linked-list-cycle-ii/有任何错误欢迎指出,有任何问题欢迎留言,谢谢观看, 视频播放量 94、弹幕量 1、点赞数 1、投硬币枚数 2、收藏人数 1、转发人数 1, 视频作者 dddeng12, 作者简介 ,相关视频:51. N 皇后 (N-queens),重
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Note: Do not modify the linked list. Follow up: Can you solve it without using extra space? 题目 给定一个链表,如果链表中存在环,则返回到链表中环的起始节点的值,如果没有环,返回null。