结果1 题目Find an equation for the line tangent to the curve at the point defined by the given value of t.x=t, y=√ (2t), t=18 ( ) A. y=- 16x B. y= 16x C. y= 16x+3 D. y=- 16x-3 相关知识点: 试题来源: 解析 C ...
根据题意:The equation of the tangent line就是求此点的切线方程,先求过此点切线的斜率:求导得:y'=(1/3)(18 -2x)^(1/3-1)=(1/3)(18 -2x)^(-2/3)=1/[3³√(18 -2x)²]把x=5代入得:y'=1/[3³√(18 -10)²]=1/[3³√64]=1/[3·(4)]=1/12即切线斜率=1/12;y=...
What is the equation of the line tangent to the curve x2+y2=100 at the point (6,8)? Answer and Explanation: Consider a function y=f(x) which is continuous and differentiable in the domain [a,b]. Consider two points lying on this curve P(x,f(x)) and Q(x+h,f...
knowledgeable and patient tutor with a ph.d. in electrical eng. see tutors like this in order to get the slope of the line tangent to the curve, we take the first order derivative of f ( x ) which is given as follows: f '( x ) = (3 - 2 x - 4 x 2 )' = -2 - 8 ...
解析 A Since risk in the graph is represented by standard deviation and P is the market portfolio, the line represents the CML.The CML is the CAL with the market portfolio as the tangency portfolio.Had risk been measured by beta, the line would be the SML....
百度试题 结果1 题目The slope of the line tangent to the curve y^2+(xy+1)^3=0 at (2,-1) is ( ) A. - 32 B. - 34 C. 0 D. 34 E. 32 相关知识点: 试题来源: 解析 D 反馈 收藏
The slope of the tangent line to the curve y = x³ at the point (1,1) is ___. A. 1 B. 2 C. 3 D. 4 相关知识点: 试题来源: 解析 C。解析:求 y = x³的导数,y' = 3x²,当 x = 1 时,斜率为 3,选项 C 正确。选项 A、B、D 都不符合。
Slope of the Tangent Line: The slope of a tangent line at some point is defined as the rate of change of the function at that point. The slope of the tangent line is the first derivative of the given equation of the curve. To evaluate the derivative of...
Find an equation of the tangent line to the curve with parametric equationsx = t sin t,y = t cos t at the point (0,−π). 相关知识点: 试题来源: 解析 于提用了专谷歌但还难隆适找5参数方提-|||-X=t sint-|||-xt'sintt+tlos't=t(sinttlas't)-|||-fsi-|||-X何=1充(0-)...
Find an equation of the tangent line to the curve at the given point.y = sin 7x + sin2 7x,(0,0)y = sin(7x) + sin^2(7x),(0,0)求方程在(0,0)点的切线方程y= 答案 y'=7cos7x+14sin7xcos7xy'(0)=7切线为y=7x相关推荐 1Find an equation of the tangent line to the curve at...