The equation of the tangent line to the curve y = (18 -2x)^1/3 at the point where x = 5 is? 答案 y = (18 -2x)^1/3x=5,y=³√(18 -10)=2;根据题意:The equation of the tangent line就是求此点的切线方程,先求过此点切线的斜率:求导得:y'=(1/3)(18 -2x)^(1/3-1)=(...
at the point (6,8)? Question: What is the equation of the line tangent to the curve x2+y2=100 at the point (6,8)? Answer and Explanation: Consider a function y=f(x) which is continuous and differentiable in the domain [a,b]. Consider two points lying on this c...
结果1 题目Find an equation for the line tangent to the curve at the point defined by the given value of t.x=t, y=√ (2t), t=18 ( ) A. y=- 16x B. y= 16x C. y= 16x+3 D. y=- 16x-3 相关知识点: 试题来源: 解析 C ...
Find an equation of the tangent line to the curve with parametric equationsx = t sin t,y = t cos t at the point (0,−π). 相关知识点: 试题来源: 解析 于提用了专谷歌但还难隆适找5参数方提-|||-X=t sint-|||-xt'sintt+tlos't=t(sinttlas't)-|||-fsi-|||-X何=1充(0-)...
百度试题 结果1 题目find an equation of the tangent line to the curve y=6xsinx at the point(π/2,3π)求y 相关知识点: 试题来源: 解析 求导y'=6(sinx+xcosx)在π/2处y'=6切线方程y-3π=6(x-π/2)即y=6x
knowledgeable and patient tutor with a ph.d. in electrical eng. see tutors like this in order to get the slope of the line tangent to the curve, we take the first order derivative of f ( x ) which is given as follows: f '( x ) = (3 - 2 x - 4 x 2 )' = -2 - 8 ...
Find an equation of the tangent line to the curve at the given point.y = sin 7x + sin2 7x,(0,0)y = sin(7x) + sin^2(7x),(0,0)求方程在(0,0)点的切线方程y= 答案 y'=7cos7x+14sin7xcos7xy'(0)=7切线为y=7x相关推荐 1Find an equation of the tangent line to the curve at...
100分求一道数学题,Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). 答案 题目意思是,求曲线 x^2y + xy^3 = 2在点(1,1)处的切线方程.对方程两边取全导,d(x^2y)+d(xy^3)=2,2xydx+x^2dy+y^3dx+3xy^2dy=0,整理得 dy/dx=-(2xy+y^...
解析 x=tcos t, y=tsin t; t=π t=π , t=π , and t=π . When t=π, (x,y)=(-π ,0) and (x,y)=(-π ,0), so an equation of the tangent to the curve at the point corresponding to t=π is y-0=π [x-(-π )], or y=π x+π ^2....
【题目】Find the equation of the tangent to the curvegiven parametrically byx=a(t+cost) y=a(1-sint) atthe pot where atthepOsintuheret=π/(4) t=π/(4) 相关知识点: 试题来源: 解析 【解析】(|x|)/(|d|)=a(1-sint) (v_1)/d=-acost⇒(v_1)/(v_1x)=(-cost)/(1-sint)...