(2))tanx : =lim_(x→+∞)(x-π/2)/(cosx)=ln1/(cos^2x)=-1 (5) lim raresinr; r) 解原式 =1; (6)lim(cotr); T 0 limn lim 解 原式 =e =e^(ln1/2m(lnx)/(ln2))=e^(-x/2x^2)=e^((x^2)/5)=e^(-1m/2)=e^(\frac(1+m , (7) lim_(x→1)x^...
Find the value : lim(x rarr0)(1+x)^((1)/(x)) 03:08 If ("lim")(xvec0)[1+x+(f(x))/x]^(1/x)=e^3, then find the value of 1n((... 06:10 Evaluate lim(x->0)((1+x)^4-1)/x 01:40 lim(x->0)(f(x))/(x^2)=1 find (i)lim(x->0)f(x)(ii)lim(x->0...
Evaluate the following : lim(xrarr 0)(1-cos mx)/(1-cos nx) , m, n b... 03:48 Evaluate the following : lim(xrarr 0)(1-cos 5x)/(1-cos 6x). 03:30 Evaluate the following : lim(xrarr 0)((1-cos 2x)/(sin^2 2x)) . ...
Evaluate the limit lim_x→ 0 sin(3x) csc(5x) Evaluate the limit. \lim\limits_{(x, y) \rightarrow (0, 0)} (x + y + 9)e^{-\frac {1}{x^2 + y^2 Evaluate the limit, given \ \lim\limits_{x\ \to\ c}\ f(x) = -\ \frac{3}{4}\ and \ \lim\limits_{x\ \...
Answer to: Evaluate lim_((x)rightarrow (0)) cos (3x) -1/x^2. By signing up, you'll get thousands of step-by-step solutions to your homework...
limx→0|x|x Question: Evaluate : limx→0|x|x Limits With Absolute Values When we face a limit of a rational function, we have to ask ourselves if the limit exists. The modulus function returns always positive values and the function1xis not defined tox=0. ...
The above property is useful to rewrite the0×∞indeterminate form of limit as quotient indeterminate form such as∞∞. Answer and Explanation:1 The given limit expression is: limx→∞x3e−x5=? The value of limit from direct substitution... ...
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2.1.1Ixsin—20xsin——cos-..解:⑴Vlim---=lim---工不存在,(因sin—,cos一为有界函数)sosinxI。cosxxx2.1xsin-]又lim---=limxsin—=0,2°sinx2°x故不能使用洛必达法则.G、..rx-sinx..]-C0SXT**(3)Vhm---=lim---不存在,18x+sinxxt...
lim(x rarr0)(ln(2-cos15x))/(ln^2(sin3x+1)) का मान बराबर है