( 3 )lg500+lg 8 5- 1 2lg64+50 ( (lg2+lg5) )^2相关知识点: 试题来源: 解析 $\left ( {1} \right )$、$2{log}_{3}2-{log}_{3}\dfrac {32} {9}+{log}_{3}8=(log)_34-(log)_3 (32) 9+(log)_38={log}_{3}\left ( {4\times \dfrac {9} {32}\times...
锥入度:LG20.1mm 型号:LG2 闪点:LG2(℃) 倾点:LG2(℃) 类别:通用脂 供应商信息 公司地址东莞市塘厦镇振兴围社区塘厦大道79号长埔建材市场J栋123号统一社会信用代码91441900059939960L 组织机构代码05993996-0注册资本10万人民币 营业期限44954-03-25至无固定期限经营状态开业 ...
2.计算下列各式.(1) lg25+lg2⋅lg50+(lg2)^21g3 2-1g9+1 lg√(27)+lg8-lg√(1000)1g0.3-1g 1.2(3) (log_32+1og_92)⋅(log_43+1og_83) . 相关知识点: 试题来源: 解析 (1-c-c+c+c-c)/((-c))=0 (51+)=5+[(+)58I^2+78I(I+58I+78I)=581+781(c81+1)+_c(78...
$lg2\cdot lg50+\left ( {lg2} \right )^{2}+lg25=lg2⋅ ( (1+lg5) )+ ( (lg2) )^2+2lg5=lg2+lg2⋅ lg5+ ( (lg2) )^2+2lg5=lg2\cdot \left ( {lg2+lg5} \right )+lg2+2lg5=2lg2+2lg5=2\left ( {lg2+lg5} \right )=2\times 1=2$, 综上所述,结论:$lg2\cdot ...
用线性插值计算误差并不大，所以最终精度还是很不错的。如果第一步不近似，用1024=25*40.96，误差...
由题意可得:原式$=lg25+lg{8}^{\dfrac {2} {3}}+lg5\times \left ( {lg4+lg5} \right )+\left ( {lg2} \right )^{2}=lg100+lg5* 2lg2+ ( (lg5) )^2+ ( (lg2) )^2=2+\left ( {lg5} \right )^{2}+2lg2lg5+\left ( {lg2} \right )^{2}$ $=2+\left ( {lg2+...
lg5×lg20+(lg2)2 Videos Oops. Something went wrong. Please try again. | Khan Academy khanacademy.org Graph quadratics: standard form | Algebra (practice) | Khan Academy khanacademy.org How To Solve Quadratic Equations By Factoring - Quick & Simple! | Algebra Online Course YouTube Compl...
计算下列各式的值:$\left(1\right)\dfrac{lg3+\dfrac{2}{5}lg9+\dfrac{3}{5}lg\sqrt{27}-lg\sqrt{3}}{lg81-lg27}$;$\left(2\right){\left(lg5\right)}^{2}+lg2\times lg50+{2}^{1+\dfrac{1}{2}{\log }_{2}5}$. 答案 跟踪训练1解(1)解法一:(正用公式)-|||-lg...
怎么计算: lg20-lg2= 1--数运算axNlg表示10底数 公式 lga + lgb=lg(ab) lga - lgb=lg(a/b) 题目代入 lg20-lg2=lg(20/2) = lg10 = 1 面公式万用公式题目都代入 答案定希望能所帮助继续问我望采纳
④lg25+lg2lg50+(lg2)2=2lg5+lg2(1+lg5)+(lg2)2=2lg5+lg2+lg2lg5+(lg2)2=2lg5+lg2+lg2(lg5+lg2)=2lg5+2lg2=2lg10=2, ⑤lg500+lg85−12lg64+50(lg2+lg5)2=lg800−lg8+50=lg100+50=52, ⑥lg27−−√+lg8−lg1000−−−−√lg1.2=32lg3+32lg4−32lg10lg...