( 3 )lg500+lg 8 5- 1 2lg64+50 ( (lg2+lg5) )^2相关知识点: 试题来源: 解析 $\left ( {1} \right )$、$2{log}_{3}2-{log}_{3}\dfrac {32} {9}+{log}_{3}8=(log)_34-(log)_3 (32) 9+(log)_38={log}_{3}\left ( {4\times \dfrac {9} {32}\times...
( 3 )$lg4+lg25=lg\left ( {4\times 25} \right )=lg{10}^{2}=2$; 综上所述,结论:$lg4+lg25=2$ $\left ( {4} \right ) ( (lg2) )^2+lg20⋅ lg5= ( (lg2) )^2+ ( (lg4+lg5) )⋅ lg5=\left ( {lg2} \right )^{2}+\left ( {2lg2+lg5} \r...
这里,我们用到了lg(2×5)=lg2+lg5\lg(2 \times 5) = \lg2 + \lg5lg(2×5)=lg2+lg5 这个对数性质。 进一步计算: 将lg(2×5)\lg(2 \times 5)lg(2×5)替换为lg10\lg10lg10,得到: lg2×lg5=lg2×lg10lg2+lg5\lg2 \times \lg5 = \frac{...
首先运用换底公式将需要求的式子转换为自然对数：lg2=ln2ln10=ln23ln2+ln54...
计算lg5×lg20+(lg2)2= . 利用对数的运算性质即可得出. 【解析】 原式=lg5×(lg5+2lg2)+(lg2)2=(lg5)2+2lg5lg2+(lg2)2=(lg5+lg2)2=1. 故答案为1. 如何用excel做excel 报表? 勤哲Excel服务器学习和下载。会Excel,懂管理,就能做excel 报表和报表。国际软博会金奖产品,深得用户信赖,万家...
计算下列各式的值:$\left(1\right)\dfrac{lg3+\dfrac{2}{5}lg9+\dfrac{3}{5}lg\sqrt{27}-lg\sqrt{3}}{lg81-lg27}$;$\left(2\right){\left(lg5\right)}^{2}+lg2\times lg50+{2}^{1+\dfrac{1}{2}{\log }_{2}5}$. 答案 跟踪训练1解(1)解法一:(正用公式) lg3+lg...
④lg25+lg2lg50+(lg2)2=2lg5+lg2(1+lg5)+(lg2)2=2lg5+lg2+lg2lg5+(lg2)2=2lg5+lg2+lg2(lg5+lg2)=2lg5+2lg2=2lg10=2, ⑤lg500+lg85−12lg64+50(lg2+lg5)2=lg800−lg8+50=lg100+50=52, ⑥lg27−−√+lg8−lg1000−−−−√lg1.2=32lg3+32lg4−32lg10lg...
设a=lg2+lg5，b=ex（x＜0），则a与b的大小关系是？a═lg2+lg5=lg10=1又b=ex，由指数函数的性质知，当x＜0时，0＜b＜1∴a＞b
Arabidopsis thaliana“extra-large GTP-binding protein” (AtXLG1). A new class of G-protein Plant Mol. Biol., 40 (1999), pp. 55-64 View in ScopusGoogle Scholar 21. L. Ding, S. Pandey, S.M. Assmann Arabidopsis extra-large G proteins (XLGs) regulate root morphogenesis Plant J., 53...
lg5×lg20+(lg2)2 Videos Oops. Something went wrong. Please try again. | Khan Academy khanacademy.org applying-the-quadratic-formula Khan Academy Khan Academy khanacademy.org ʕ•ᴥ•ʔ Quadratic Functions - Explained, Simplified and Made Easy YouTube Factoring Quadratic Expressions Pt....